**Synthesis of Carboxylic Acid**Objective: Devise the most efficient synthesis for the carboxylic acid shown below using a starting material and reagents from the tables provided.### Target Carboxylic Acid:The structure shown is a carboxylic acid with a long alkyl chain.### Starting Materials:1. Benzyl bromide (with benzene ring)2. p-bromotoluene3. 1-bromopentane4. t-butanol5. Hexanal6. 2-methyl-2-propanol7. 4-bromo-1-butanol8. 1-octene### Reagents:- **a**: Mg / dry ether- **b**: 1. CO₂ 2. acidic workup- **c**: NaCN / THF or DMF- **d**: NaCN / dil. aqueous H₂SO₄- **e**: Ethanol, H₂SO₄(trace) at reflux- **f**: Conc. HCl- **g**: HBr- **h**: KOH / alcohol- **i**: OsO₄- **j**: Na₂CrO₄ / aqueous H₂SO₄- **k**: 1. BH₃/THF 2. H₂O₂/aq. NaOH- **l**: Epoxide### Instruction:To specify your synthesis route, select the number of the starting material followed by the letters corresponding to the reagents. Begin with the first step.Example Pathway:- The answer 4fh means treat t-butanol (4) with conc. HCl (f), then treat the product with KOH in alcohol (h).Make sure to carefully choose the right combination of starting materials and reagents to achieve the desired carboxylic acid efficiently. Consider factors like reactivity, selectivity, and ease of purification.

Interpretation - Most efficient route of synthesis for the given carboxylic acid is to be proposed.Given carboxylic acid contain 8 carbon atoms. Reagent 8 has 8 carbon atoms. Hydroboration of alkene gives alcohol. Regiochemistry- Anti-Markovnikov (OH gets attached to that carbon which contain more number of hydrogen atoms) Stereochemistry- Syn-addition Oxidation of primary alcohol with strong oxidizing agents like Na2CrO4 in H2SO4 produces carboxylic acids. Hence, Starting material 8 Reagent k followed by j will give desired carboxylic acid. Synthesis is efficient as- first reaction is stereospecific No possibility of formation of other anti product or another isomer. Synthesis in two steps. Answer- 8kj