Determine v(t) for t2 0 for the circuit of Figure P 7.2-10a when v(0) = -4 V and is(t) is the current shown in Figure. Find the value of A,B,C,D and E. The value of v(t) for the time interval 0 ≤ t≤ 0.25 is in the form A+Bt² The value of v(t) for the time interval 0.25 ≤t≤ 0.5 is in the form C+Dt The value of v(t) for the time interval 0.5 ≤ t is in the form E is (t) M 2Ω + 0.1 F= v(t) -
Determine v(t) for t2 0 for the circuit of Figure P 7.2-10a when v(0) = -4 V and is(t) is the current shown in Figure. Find the value of A,B,C,D and E. The value of v(t) for the time interval 0 ≤ t≤ 0.25 is in the form A+Bt² The value of v(t) for the time interval 0.25 ≤t≤ 0.5 is in the form C+Dt The value of v(t) for the time interval 0.5 ≤ t is in the form E is (t) M 2Ω + 0.1 F= v(t) -
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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I cant solve for part C and I don't know what I am doing wrong and still ending up with the overall right answer.

Transcribed Image Text:This graph depicts the current \( i_S \) in amperes (A) as a function of time \( t \) in seconds (s). The vertical axis represents the current, with markings at 1 and 2 amperes, while the horizontal axis represents time, marked at 0.25 and 0.5 seconds.
**Graph Description:**
- The graph begins at the origin (0,0), indicating a zero current at time \( t = 0 \).
- From \( t = 0 \) to \( t = 0.25 \) seconds, the current linearly increases, reaching a maximum of 2 amperes.
- Between \( t = 0.25 \) and \( t = 0.5 \) seconds, the current remains constant at 2 amperes.
- After \( t = 0.5 \) seconds, the current abruptly returns to zero amperes.
This graph is labeled "(b)" below the horizontal axis. It visually represents a piecewise linear function, showing the rising, constant, and falling phases of the current over the specified time interval.
![**P7.2.10 (Questions 1 to 5)**
Determine \( v(t) \) for \( t \geq 0 \) for the circuit of Figure P 7.2-10a when \( v(0) = -4 \, \text{V} \) and \( i_s(t) \) is the current shown in Figure. **Find the value of A, B, C, D, and E.**
The value of \( v(t) \) for the time interval \( 0 \leq t \leq 0.25 \) is in the form
\[ A + Bt^2 \]
The value of \( v(t) \) for the time interval \( 0.25 \leq t \leq 0.5 \) is in the form
\[ C + Dt \]
The value of \( v(t) \) for the time interval \( 0.5 \leq t \) is in the form
\[ E \]
**Diagram Description:**
The circuit diagram (Figure P 7.2-10a) consists of a simple series circuit with the following components:
- A current source \( i_s(t) \) oriented upwards.
- A resistor with a resistance of \( 2 \, \Omega \) connected in series with the current source.
- A capacitor with a capacitance of \( 0.1 \, \text{F} \) connected across the output, with its voltage designated as \( v(t) \).
The positive terminal of the capacitor is on the top, indicating the direction of positive voltage.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe3513363-cb6f-4339-8b85-3b7b98137f18%2F7615febf-e8c3-410b-b038-ba7bf834172a%2Fom79j5i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**P7.2.10 (Questions 1 to 5)**
Determine \( v(t) \) for \( t \geq 0 \) for the circuit of Figure P 7.2-10a when \( v(0) = -4 \, \text{V} \) and \( i_s(t) \) is the current shown in Figure. **Find the value of A, B, C, D, and E.**
The value of \( v(t) \) for the time interval \( 0 \leq t \leq 0.25 \) is in the form
\[ A + Bt^2 \]
The value of \( v(t) \) for the time interval \( 0.25 \leq t \leq 0.5 \) is in the form
\[ C + Dt \]
The value of \( v(t) \) for the time interval \( 0.5 \leq t \) is in the form
\[ E \]
**Diagram Description:**
The circuit diagram (Figure P 7.2-10a) consists of a simple series circuit with the following components:
- A current source \( i_s(t) \) oriented upwards.
- A resistor with a resistance of \( 2 \, \Omega \) connected in series with the current source.
- A capacitor with a capacitance of \( 0.1 \, \text{F} \) connected across the output, with its voltage designated as \( v(t) \).
The positive terminal of the capacitor is on the top, indicating the direction of positive voltage.
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