I cant solve for part C and I don't know what I am doing wrong and still ending up with the overall right answer. This graph depicts the current \( i_S \) in amperes (A) as a function of time \( t \) in seconds (s). The vertical axis represents the current, with markings at 1 and 2 amperes, while the horizontal axis represents time, marked at 0.25 and 0.5 seconds.**Graph Description:**- The graph begins at the origin (0,0), indicating a zero current at time \( t = 0 \).- From \( t = 0 \) to \( t = 0.25 \) seconds, the current linearly increases, reaching a maximum of 2 amperes.- Between \( t = 0.25 \) and \( t = 0.5 \) seconds, the current remains constant at 2 amperes.- After \( t = 0.5 \) seconds, the current abruptly returns to zero amperes.This graph is labeled "(b)" below the horizontal axis. It visually represents a piecewise linear function, showing the rising, constant, and falling phases of the current over the specified time interval. **P7.2.10 (Questions 1 to 5)**Determine \( v(t) \) for \( t \geq 0 \) for the circuit of Figure P 7.2-10a when \( v(0) = -4 \, \text{V} \) and \( i_s(t) \) is the current shown in Figure. **Find the value of A, B, C, D, and E.**The value of \( v(t) \) for the time interval \( 0 \leq t \leq 0.25 \) is in the form \[ A + Bt^2 \]The value of \( v(t) \) for the time interval \( 0.25 \leq t \leq 0.5 \) is in the form \[ C + Dt \]The value of \( v(t) \) for the time interval \( 0.5 \leq t \) is in the form \[ E \]**Diagram Description:**The circuit diagram (Figure P 7.2-10a) consists of a simple series circuit with the following components:- A current source \( i_s(t) \) oriented upwards.- A resistor with a resistance of \( 2 \, \Omega \) connected in series with the current source.- A capacitor with a capacitance of \( 0.1 \, \text{F} \) connected across the output, with its voltage designated as \( v(t) \). The positive terminal of the capacitor is on the top, indicating the direction of positive voltage.

A circuit,where the current is(t) is, and v(0)=-4 V, for time , the value of v(t) is in the form . for time , the value of v(t) is in the form . for time , the value of v(t) is in the form E. we need to find:the values of A, B, C, D, and E. Given current waveform can be represented mathematically as,Required coefficients are:

Engineering

Electrical Engineering

Determine v(t) for t2 0 for the circuit of Figure P 7.2-10a when v(0) = -4 V and is(t) is the current shown in Figure. Find the value of A,B,C,D and E. The value of v(t) for the time interval 0 ≤ t≤ 0.25 is in the form A+Bt² The value of v(t) for the time interval 0.25 ≤t≤ 0.5 is in the form C+Dt The value of v(t) for the time interval 0.5 ≤ t is in the form E is (t) M 2Ω + 0.1 F= v(t) -

Determine v(t) for t2 0 for the circuit of Figure P 7.2-10a when v(0) = -4 V and is(t) is the current shown in Figure. Find the value of A,B,C,D and E. The value of v(t) for the time interval 0 ≤ t≤ 0.25 is in the form A+Bt² The value of v(t) for the time interval 0.25 ≤t≤ 0.5 is in the form C+Dt The value of v(t) for the time interval 0.5 ≤ t is in the form E is (t) M 2Ω + 0.1 F= v(t) -

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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