Am I doing this correct?Determine the support reactions/reactions Determine the support reactions:Ax4m4 m150kN6 m425 kN/m-10 mS36-87P₁= 25 (10) = 2500P₂ = 150Bytan= 1951.38 KN2== 36.87-90EMA=0 +-By Los (53.130) (8) - By Sin (53.130) (16) + 2500 (11)+= 53.130

Answered: Image /qna-images/answer/0322a03f-334d-48da-82ce-a6563ee4823c.jpg

Determine the support reactions: Ax 4 m 4 m 150 kN 6 m 4 A 25 kN/m - 10 m S 34-87 P₁= 25 (10) = 2500 P₂ = 150 By: = 1951.38 KN tan 2= = 36.87-90 EMA=0 + -By los (53.130) (8) - By sin (53.130) (16) + 2500 (11) + = 53.130

Determine the support reactions: Ax 4 m 4 m 150 kN 6 m 4 A 25 kN/m - 10 m S 34-87 P₁= 25 (10) = 2500 P₂ = 150 By: = 1951.38 KN tan 2= = 36.87-90 EMA=0 + -By los (53.130) (8) - By sin (53.130) (16) + 2500 (11) + = 53.130

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Question

Am I doing this correct? Determine the support reactions/reactions

Determine the support reactions:
Ax
4m
4 m
150
kN
6 m
4
25 kN/m
-10 m
S
36-87
P₁= 25 (10) = 2500
P₂ = 150
By
tan
= 1951.38 KN
2=
= 36.87-90
EMA=0 +
-By Los (53.130) (8) - By Sin (53.130) (16) + 2500 (11)
+
= 53.130

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Step 1: Draw the free body diagram of the given beam

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