I know what the answer is to this question (per the textbook) but I'm not sure how to solve the second part of the question: determine the standard deviation temperature. Also, the first part of the question, I calculate 70.28 as the mean but the answer is 70.6. How should I have rounded that? Household WinterTemperature Often,frequency distributions arereported using unequal classwidths because thefrequencies of some groupswould otherwise be small orvery large. Consider thefollowing data, which representthe daytime householdtemperature the thermostat isset to when someone is homefor a random sample of 750households. Determinethe class midpoint, ifnecessary, for each class andapproximate the mean andstandard deviationtemperature.Source: Based on data from the U.S. Department of EnergyFrequency Midpoint - xi31Temperature (°F)(°F)61-6465-6768-69xi fi62.50001937.500006766.00004422.0000019819568.500013563.000007071-7270.000013650.0000012071.50008580.00000895073-7674.50006630.5000077-8078.50003925.0000075052708.00000Mean70.28| |유

Name: I know what the answer is to this question (per the textbook) but I'm
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Description: I know what the answer is to this question (per the textbook) but I'm not sure how to solve the second part of the question: determine the standard deviation temperature. Also, the first part of the question, I calculate 70.28 as the mean but the a

Provided data is: Temperature Frequency 61 – 64 31 65 – 67 67 68 – 69 198…

Answered: determine the standard deviation…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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I know what the answer is to this question (per the textbook) but I'm not sure how to solve the second part of the question: determine the standard deviation temperature. Also, the first part of the question, I calculate 70.28 as the mean but the answer is 70.6. How should I have rounded that?

Household Winter
Temperature Often,
frequency distributions are
reported using unequal class
widths because the
frequencies of some groups
would otherwise be small or
very large. Consider the
following data, which represent
the daytime household
temperature the thermostat is
set to when someone is home
for a random sample of 750
households. Determine
the class midpoint, if
necessary, for each class and
approximate the mean and
standard deviation
temperature.
Source: Based on data from the U.S. Department of Energy
Frequency Midpoint - xi
31
Temperature (°F)(°F)
61-64
65-67
68-69
xi fi
62.5000
1937.50000
67
66.0000
4422.00000
198
195
68.5000
13563.00000
70
71-72
70.0000
13650.00000
120
71.5000
8580.00000
89
50
73-76
74.5000
6630.50000
77-80
78.5000
3925.00000
750
52708.00000
Mean
70.28
| |유

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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