Assume that adults have IQ scores that are normally distributed with a mean of 105 and a standard deviation 15. Find P,, which is the IQ score separating the bottom 2% from the top 98%. Click to view page 1 of the table. Click to view page 2 of the table. The IQ score that separates the bottom 2% from the top 98% is P, =. (Round to the nearest hundredth as needed.)

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### Problem 6.3.17

Assume that adults have IQ scores that are normally distributed with a mean of 105 and a standard deviation of 15. Find \( P_2 \), which is the IQ score separating the bottom 2% from the top 98%.

- Click to view [page 1 of the table](#).
- Click to view [page 2 of the table](#).

The IQ score that separates the bottom 2% from the top 98% is \( P_2 = \) ____.
(Round to the nearest hundredth as needed.)

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### Answer Submission

Enter your answer in the answer box and then click Check Answer.

---

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### Instruction to Answer:

1. Identify the Z-score that corresponds to the bottom 2% of the distribution using a Z-table or standard normal distribution table.
2. Use the formula to convert the Z-score to an IQ score:
   \[ IQ = \mu + Z \times \sigma \]
   where \(\mu\) is the mean (105) and \(\sigma\) is the standard deviation (15).
3. Round your answer to the nearest hundredth as needed.
4. Submit your answer in the provided answer box.
Transcribed Image Text:### Problem 6.3.17 Assume that adults have IQ scores that are normally distributed with a mean of 105 and a standard deviation of 15. Find \( P_2 \), which is the IQ score separating the bottom 2% from the top 98%. - Click to view [page 1 of the table](#). - Click to view [page 2 of the table](#). The IQ score that separates the bottom 2% from the top 98% is \( P_2 = \) ____. (Round to the nearest hundredth as needed.) --- ### Answer Submission Enter your answer in the answer box and then click Check Answer. --- All parts showing ### Instruction to Answer: 1. Identify the Z-score that corresponds to the bottom 2% of the distribution using a Z-table or standard normal distribution table. 2. Use the formula to convert the Z-score to an IQ score: \[ IQ = \mu + Z \times \sigma \] where \(\mu\) is the mean (105) and \(\sigma\) is the standard deviation (15). 3. Round your answer to the nearest hundredth as needed. 4. Submit your answer in the provided answer box.
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