**Problem Statement: Graph Transformation** Given: Let \( f(x) = 4\sqrt{x} \). **Task:** If \( g(x) \) is the graph of \( f(x) \) shifted down 6 units and left 1 unit, write a formula for \( g(x) \). **Solution:** - The transformation of a function \( f(x) \) by shifting it horizontally to the left by \( h \) units is given by \( f(x + h) \). - Vertically shifting the graph down by \( k \) units is achieved by subtracting \( k \) from the function, resulting in \( f(x) - k \). **Applying the transformations:** 1. Shift left by 1 unit: Replace \( x \) with \( x + 1 \) in \( f(x) \). \[ f(x+1) = 4\sqrt{x+1} \] 2. Shift down by 6 units: Subtract 6 from the function. \[ g(x) = 4\sqrt{x+1} - 6 \] Thus, the formula for \( g(x) \) is: \[ g(x) = 4\sqrt{x+1} - 6 \] **Instructions:** - Enter \( \sqrt{x} \) as `sqrt(x)`. - For further assistance, select "Message instructor." - [Submit Question Button]
Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
How do I solve?
Given that, the graph of the function is and also given that, the function shifted down 6 units and left 1 unit.
"Vertical Shifts:
If c is a positive real number, the graph of the graph of shifted upward c units.
If c is a positive real number, the graph of the graph of shifted downward c units.
Horizontal Shift:
If c is a positive real number, then the graph of is the graph of shifted to the right c units.
If c is a positive real number, then the graph of is the graph of shifted to the left c units.."
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