**Problem Statement: Graph Transformation** Given: Let \( f(x) = 4\sqrt{x} \). **Task:** If \( g(x) \) is the graph of \( f(x) \) shifted down 6 units and left 1 unit, write a formula for \( g(x) \). **Solution:** - The transformation of a function \( f(x) \) by shifting it horizontally to the left by \( h \) units is given by \( f(x + h) \). - Vertically shifting the graph down by \( k \) units is achieved by subtracting \( k \) from the function, resulting in \( f(x) - k \). **Applying the transformations:** 1. Shift left by 1 unit: Replace \( x \) with \( x + 1 \) in \( f(x) \). \[ f(x+1) = 4\sqrt{x+1} \] 2. Shift down by 6 units: Subtract 6 from the function. \[ g(x) = 4\sqrt{x+1} - 6 \] Thus, the formula for \( g(x) \) is: \[ g(x) = 4\sqrt{x+1} - 6 \] **Instructions:** - Enter \( \sqrt{x} \) as `sqrt(x)`. - For further assistance, select "Message instructor." - [Submit Question Button]

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Problem Statement: Graph Transformation**

Given:

Let \( f(x) = 4\sqrt{x} \).

**Task:**

If \( g(x) \) is the graph of \( f(x) \) shifted down 6 units and left 1 unit, write a formula for \( g(x) \).

**Solution:**

- The transformation of a function \( f(x) \) by shifting it horizontally to the left by \( h \) units is given by \( f(x + h) \).
- Vertically shifting the graph down by \( k \) units is achieved by subtracting \( k \) from the function, resulting in \( f(x) - k \).

**Applying the transformations:**

1. Shift left by 1 unit: Replace \( x \) with \( x + 1 \) in \( f(x) \).
   \[
   f(x+1) = 4\sqrt{x+1}
   \]

2. Shift down by 6 units: Subtract 6 from the function.
   \[
   g(x) = 4\sqrt{x+1} - 6
   \]

Thus, the formula for \( g(x) \) is:
\[
g(x) = 4\sqrt{x+1} - 6
\]

**Instructions:**

- Enter \( \sqrt{x} \) as `sqrt(x)`.
- For further assistance, select "Message instructor."

- [Submit Question Button]
Transcribed Image Text:**Problem Statement: Graph Transformation** Given: Let \( f(x) = 4\sqrt{x} \). **Task:** If \( g(x) \) is the graph of \( f(x) \) shifted down 6 units and left 1 unit, write a formula for \( g(x) \). **Solution:** - The transformation of a function \( f(x) \) by shifting it horizontally to the left by \( h \) units is given by \( f(x + h) \). - Vertically shifting the graph down by \( k \) units is achieved by subtracting \( k \) from the function, resulting in \( f(x) - k \). **Applying the transformations:** 1. Shift left by 1 unit: Replace \( x \) with \( x + 1 \) in \( f(x) \). \[ f(x+1) = 4\sqrt{x+1} \] 2. Shift down by 6 units: Subtract 6 from the function. \[ g(x) = 4\sqrt{x+1} - 6 \] Thus, the formula for \( g(x) \) is: \[ g(x) = 4\sqrt{x+1} - 6 \] **Instructions:** - Enter \( \sqrt{x} \) as `sqrt(x)`. - For further assistance, select "Message instructor." - [Submit Question Button]
Expert Solution
Step 1

Given that, the graph of the function is fx=4x and also given that, the function shifted down 6 units and left 1 unit.

"Vertical Shifts:

If c is a positive real number, the graph of  fx+c the graph of y=fx shifted upward c units.

 If c is a positive real number, the graph of  fx-c the graph of y=fx shifted downward c units.

Horizontal Shift:

If c is a positive real number, then the graph of  fx-c is  the graph of y=fx shifted to the right c units.

If c is a positive real number, then the graph of  fx+c is  the graph of y=fx shifted to the left c units.."  

                     

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