Determine the reaction-rate law and the value of the rate constant. 2 NO(g) + Br2(g) → 2 NOBr(g)   Answer: rate of reaction = (1.30 × 10–3 M–2 . min–1)[NO]2[Br2]

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Determine the reaction-rate law and the value of the rate constant.

2 NO(g) + Br2(g) → 2 NOBr(g)

 

Answer: rate of reaction = (1.30 × 10–3 M–2 . min–1)[NO]2[Br2]

I need steps, I don't know how to get the exponent for NO as 2, i keep getting it as a first order reaction. 

[NO],/M [Br,]o/M
(rate of reaction)/M•min
-1
Run
1
1.00
1.00
1.30 × 10-3
2
1.50
1.00
2.93 × 10-3
3
1.50
3.00
8.78 × 10-3
Transcribed Image Text:[NO],/M [Br,]o/M (rate of reaction)/M•min -1 Run 1 1.00 1.00 1.30 × 10-3 2 1.50 1.00 2.93 × 10-3 3 1.50 3.00 8.78 × 10-3
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