Determine the rate of formation of HBr considering the mechanism of chain reaction, i.e.: (a) Initiation: Br2 - 2Br (b) Propagation of the chain: k2/k2 Br +H2 HBr + H' (radical) k3 Н + Brz (cycle of 106 times) HBr|+ Br* (c) Termination: 2Br- k4 Br2

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