Determine the quantities of materials required per cubic yard to create a concrete mix. The specifications require a maximum size aggregate of 1½ in., a minimum cement content of 5½ sacks per cy, and a maximum water-cement ratio of 0.60. Assume 6% air voids (cement, 470 lb per cy; water, 4.52 cf/cy; fine aggregate, 1,068 lb/cy; coarse aggregate, 1,986 lb/cy).

Solution:- Given data:- The maximum size of aggregates of 112in The minimum cement content = 512sacks/cy Assume air voids = 6% To find:- The quantities of material. Calculation:- 1) To find weight of cement = No.of cement bags × weight of each bag∴ weight of cement = 5 ×94∴ weight of cement = 470 lb/yard3Now,2) To find weight of water= w/c ratio ×weight of cement ∴ weight of cement =0.6 × 470∴ weight of cement = 282 lb/yard3So,Volume of water = 2821×62.4 ....(weight of water= 62.4 lb/ft3)∴ Volume of water = 4.52 cubic ft/cubic yrdCalculation:- Now, Determine the volume of aggregate Here, Here,Volume of air = 6100×27∴ Volume of air =1.62 cubic ft/cubic yrdVolume of aggregate =27-(2.39) - volume of water-1.62Here,27 is the total voume and 2.39 is the cement volume∴ Volume of aggregate =27-(2.39) -4.52-1.62∴ Volume of aggregate =18.47 cubic ft/cubic yrdTherefore,Volume of sand:35% of fine aggregate in total volume of aggregate∴ Volume of sand =0.35×18.47∴ Volume of sand = 6.46 cu.ft/cu.yrdNow,Weight of fine aggregate = 6.46×2.65×62.4∴ Weight of fine aggregate =1068.23 lb/cu yrdNow, Weight of coarse aggregate = (volume of aggregate - volume of fine aggregate or sand)×2.65×62.4Weight of coarse aggregate =(18.47 - 6.46)×2.65×62.4∴ Weight of coarse aggregate =1985.97≃1986 lb/cu yrdConclusion:- The quantities of material:- 1.Weight of cement = 470 lb/cu.yrd 2.Volume of water = 4.52 cu.ft/cu.yrd 3.Weight of fine aggregate = 1068.23 lb/cu.yrd 4. Weight of coarse aggregate = 1986 lb/cu.yrd

Engineering

Civil Engineering

Determine the quantities of materials required per cubic yard to create a concrete mix. The specifications require a maximum size aggregate of 1 in., a minimum cement content of 5 sacks per cy, and a maximum water- cement ratio of 0.60. Assume 6% air voids (cement, 470 lb per cy; water, 4.52 cf/cy; fine aggregate, 1,068 lb/cy; coarse aggregate, 1,986 lb/cy).

Determine the quantities of materials required per cubic yard to create a concrete mix. The specifications require a maximum size aggregate of 1 in., a minimum cement content of 5 sacks per cy, and a maximum water- cement ratio of 0.60. Assume 6% air voids (cement, 470 lb per cy; water, 4.52 cf/cy; fine aggregate, 1,068 lb/cy; coarse aggregate, 1,986 lb/cy).

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Types of Cement

Cement is a fine mixture of limestone, chalk, or marl and clay which when mixed with water, becomes compacted due to the formation of strong molecular bonds. Due to hydration, cement turns into a hard mass when left for a sufficient amount of time upon mixing with water. The water turns the cement compounds into gel-like submicroscopic particles having higher surface areas. It is due to the hydration properties of cement, they are often known as hydraulic cement. For instance, Portland cement is a popular example in this category.

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Determine the quantities of materials required per cubic yard to create a concrete mix. The specifications require a maximum size aggregate of 1½ in., a minimum cement content of 5½ sacks per cy, and a maximum water-cement ratio of 0.60. Assume 6% air voids (cement, 470 lb per cy; water, 4.52 cf/cy; fine aggregate, 1,068 lb/cy; coarse aggregate, 1,986 lb/cy).

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