Determine the pH of a solution of HF by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The Ka of HF is 6.8 x 10-4. Complete Parts 1-3 before submitting your answer. NEXT > A 0.30 M aqueous solution of HF is prepared. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) -2x 6.8 x 10-4-2x 0 1 0.30 + x HF(aq) 0.30 0.30 - x + 2 H₂O(1) 6.8 x 10-4 0.30 + 2x 0.15 0.30 - 2x 3 H3O+(aq) + +X 6.8 x 10-4 + x -X 6.8 x 10-4-x F-(aq) RESET +2x 6.8 x 10-4 + 2x
Determine the pH of a solution of HF by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The Ka of HF is 6.8 x 10-4. Complete Parts 1-3 before submitting your answer. NEXT > A 0.30 M aqueous solution of HF is prepared. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) -2x 6.8 x 10-4-2x 0 1 0.30 + x HF(aq) 0.30 0.30 - x + 2 H₂O(1) 6.8 x 10-4 0.30 + 2x 0.15 0.30 - 2x 3 H3O+(aq) + +X 6.8 x 10-4 + x -X 6.8 x 10-4-x F-(aq) RESET +2x 6.8 x 10-4 + 2x
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Determine the pH of a solution of HF by constructing an ICE table, writing the
equilibrium constant expression, and using this information to determine the pH. The
Ka of HF is 6.8 x 10-4. Complete Parts 1-3 before submitting your answer.
NEXT >
A 0.30 M aqueous solution of HF is prepared. Fill in the ICE table with the appropriate value for each
involved species to determine concentrations of all reactants and products.
Initial (M)
Change (M)
Equilibrium (M)
-2x
6.8 x 10-4-2x
0
0.30 + x
1
HF(aq)
0.30
0.30 - x
+
H₂O(l)
6.8 x 10-4
2
0.30 + 2x
0.15
0.30 - 2x
H3O+(aq) +
+X
3
6.8 x 104 + x
-X
6.8 x 10-4-x
F-(aq)
✓ RESET
+2x
6.8 x 10-4 + 2x
![Determine the pH of a solution of HF by constructing an ICE table, writing the
equilibrium constant expression, and using this information to determine the pH. The
Ka of HF is 6.8 x 10-4. Complete Parts 1-3 before submitting your answer.
< PREV
3
NEXT >
Based on your ICE table and the definition of Ka, set up the expression for Ka in order to determine
the unknown. Each reaction participant must be represented by one tile. Do not combine terms.
[0]
[0.30 -x]
[0.30]
[0.30 + 2x]
1
Ka
=
[6.8 x 10-4]
[0.30 - 2x]
[0.15]
[6.8 x 10-4+x]
2
= 6.8 × 10-4
[6.8 x 10-4-x]
[2x]
[6.8 x 10-4 + 2x]
[2x]²
[6.8 x 10-4-2x]
RESET
[0.30 + x]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6fb406b3-dfb5-4d65-a424-9ec71ae4c6de%2Fe996dccc-1c19-4eb8-a05e-a7210920c884%2F0yx422t_processed.png&w=3840&q=75)
Transcribed Image Text:Determine the pH of a solution of HF by constructing an ICE table, writing the
equilibrium constant expression, and using this information to determine the pH. The
Ka of HF is 6.8 x 10-4. Complete Parts 1-3 before submitting your answer.
< PREV
3
NEXT >
Based on your ICE table and the definition of Ka, set up the expression for Ka in order to determine
the unknown. Each reaction participant must be represented by one tile. Do not combine terms.
[0]
[0.30 -x]
[0.30]
[0.30 + 2x]
1
Ka
=
[6.8 x 10-4]
[0.30 - 2x]
[0.15]
[6.8 x 10-4+x]
2
= 6.8 × 10-4
[6.8 x 10-4-x]
[2x]
[6.8 x 10-4 + 2x]
[2x]²
[6.8 x 10-4-2x]
RESET
[0.30 + x]
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