!Required InformationConsider the given state of stress. Take X= 16 MPa and Y= 48 MPa.The+60 MPaDetermine the orientation of the planes of maximum In-plane shearing stress using Mohr's circle.of the plane of maximum in-plane shearing ressfirst quadrant isThe orientation of the plane of maximum in-plane shearing stress in the second quadrant is

Answered: Image /qna-images/answer/7243ec4a-ab72-4636-95b2-c5ea07e47dc8.jpg

Determine the orientation of the planes of maximum In-plane shearing stress using Mohr's circle. The orientation of the plane of maximum in-plane shearing stress in the first quadrant is [ The orientation of the plane of maximum in-plane shearing stress in the second quadrant is

Determine the orientation of the planes of maximum In-plane shearing stress using Mohr's circle. The orientation of the plane of maximum in-plane shearing stress in the first quadrant is [ The orientation of the plane of maximum in-plane shearing stress in the second quadrant is

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Q1/ For the state of plane stress shown below, construct a Mohr's circle and determine:- (a) the principle stress acting at this point (b) the orientation of the principle stress (c) the maximum in-plane shear stress at the point and the corresponding average normal stress (d) the orientation of the maximum in-plane shear stress (e) show the results on elements 700 kPa pisres shear Stress at 100 kPa al stress aximum plar arenis ec 400 kPa
The state of plane stress at a point with respect to the xy-axes is shown in Fig. (a). Using Mohr's circle, determine (1) the principal stresses and principal planes; (2) the maximum in-plane shear stress; and (3) the equivalent state of stress with respect to the x'y'-axes. Show all results on sketches of properly oriented elements. y20 MPa 50° 40 MPa 16 MPa (a)
The state of stress at a point in a soil beneath a level ground surface consists of a major principal stress of 70 kPa and a minor principal stress of 25 kPa. The major principal stress acts in the vertical direction. (a) Draw the Mohr's circle of stress and show the pole point (origin of planes). (b) Determine the maximum shear stress and calculate the orientation angle (relative to horizontal) of the plane of positive maximum shear stress. (c) Determine the normal stress and shear stress on a plane that makes an angle of -20° (i.e., 20° clockwise) relative to the horizontal plane.
Required information Consider the given state of stress. Take X = 8 ksi and Y= 4 ksi. + + 4 ksi X Determine the orientation of the planes of maximum in-plane shearing stress. The orientations of the planes of maximum in-plane shearing stress are O and
5. Determine the normal stress and shear stress acting on the inclined plane AB. Scive the problem using the stress transformation equations Show the resut on the sectioned eement, 45 MPa 80 MPa
Q1/ For the state of plane stress shown below, construct a Mohr's circle and determine:- (a) the principle stress acting at this point (b) the orientation of the principle stress (c) the maximum in-plane shear stress at the point and the corresponding average normal stress (d) the orientation of the maximum in-plane shear stress (e) show the results on elements 700 kPa 100 kPa tal stress enks 400 kPa
Determine the resulting maximum value of the normal stress. Specify the orientation of the plane on which these maximum values occur. **The answer is tensile stress is 0 ksi at 90 degrees. **The answer is compressive stress is 7 ksi at 0 degrees. Can you explain how that is? This was my thought process: I know that tensile would be zero because the force P is actually going inwards and not outwards. I know that means that there would be a compressive force. I am confused on the angles, how is a tensile force going 90 degress if there technically is no force in the tensile direction. And how is there a compressive force at 90 degrees if there is a stress? thank you!
Consider the given state of stress. Take X = 12 MPa and Y= 55 MPa. Y X 60 MPa Determine the maximum in-plane shearing stress using Mohr's circle. The maximum in-plane shearing stress is MPa.
3. (a) Using Stress transformation equations, determine the principal planes, the principal stresses, the maximum in-plane shear stress and the corresponding normal stress. (b) Solve part (a) using Mohr's circle. 100 MPa 75 MPa 150 MPa
Required information Consider the given state of stress. Take Y = 4 ksi. 10 ksi ces Determine the normal and shearing stresses after the element shown has been rotated through 10 counterclockwise. The normal stress oy is ksi and oy'is ksi, The shear stress Tyyis ksi
The 20 mm diameter rod is subjected to the loads shown. (a) Determine the state of stress at point A and show the results on a differential element located at this point. (b) Using Mohr's circle, determine the maximum normal stress and the maximum in-plane shearing stress at point A and show the associated stress states on appropriately oriented elements, for each case. 75 mm 375 N B 200 mm 450 N
4 ksi The state of plane stress at a point is shown on the element. (a) Draw Mohr's circle neatly to scale, and use it to complete part (b). (b) Determine the state of stress on an element rotated 35° counterclock- 20 ksi wise from the given element. Sketch the state of stress on the rotated element element. 9 ksi -20 -10 o (ksi) -30 -20 -10 10 20 30 10 20 T (ksi)