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Determine the hydraulic diameter and hydraulic radius for the open trapezoidal channel shown using the definition. Given that b = 4.7, T= 7.0, and h = 2.7 (all dimensions measured in ft). If the flow rate is Q = 30.0 cfs, identify the flow in the channel to be subcritical, critical or supercritical and find the alternative depth if it is not critical.

Determine the hydraulic diameter and hydraulic radius for the open trapezoidal channel shown using the definition. Given that b = 4.7, T= 7.0, and h = 2.7 (all dimensions measured in ft). If the flow rate is Q = 30.0 cfs, identify the flow in the channel to be subcritical, critical or supercritical and find the alternative depth if it is not critical.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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Fluid Mechanics Hw #9
Determine the hydraulic diameter and hydraulic radius for the open trapezoidal channel shown using the definition. Given that b = 4.7, T= 7.0, and h=2.7 (all dimensions measured in ft). If the flow rate is Q = 30.0 cfs, identify the flow in the channel to be subcritical, critical or supercritical and find the alternative depth if it is not critical. Solution: 1. Side slope m = 2. Flow area A = 3. Wetted perimeter Pw= 4. Hydraulic radius Rh = 5. Hydraulic depth Dh = 6. Froude number Fr = 7. The flow is 8. Specific energy E = 9. Alternative depth y' = ft²; 1 ft; ft; ft; +5 ft; T b h
Transcribed Image Text:Determine the hydraulic diameter and hydraulic radius for the open trapezoidal channel shown using the definition. Given that b = 4.7, T= 7.0, and h=2.7 (all dimensions measured in ft). If the flow rate is Q = 30.0 cfs, identify the flow in the channel to be subcritical, critical or supercritical and find the alternative depth if it is not critical. Solution: 1. Side slope m = 2. Flow area A = 3. Wetted perimeter Pw= 4. Hydraulic radius Rh = 5. Hydraulic depth Dh = 6. Froude number Fr = 7. The flow is 8. Specific energy E = 9. Alternative depth y' = ft²; 1 ft; ft; ft; +5 ft; T b h
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