Determine the gradient of the circular storm/surface water pipe by using the Chezy Formul with the following information: Q = 0.01 m³/s Wetted area of pipe: A= 0.02 m? v = C x Vmi C = 55 Flow rate of water: Chezy formula: Chezy coefficient: Hydraulic mean depth: m= d /4 Diameter of pipe: d = 150 mm %3D

Determine the gradient of the circular storm/surface water pipe by using the Chezy Formul with the following information: Q = 0.01 m³/s Wetted area of pipe: A= 0.02 m? v = C x Vmi C = 55 Flow rate of water: Chezy formula: Chezy coefficient: Hydraulic mean depth: m= d /4 Diameter of pipe: d = 150 mm %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

What is the entrance length in a 4-cm-diameter pipe if 0.5*10^ -4 m^ 3 / s water is flowing
Find the value of hydraulic radius Wetted area=50 m2 Wetted perimeter=25 m
On a circular conduit there are different diameters: diameter D1 = 2 m, changes into D2 = 3 m. The velocity in the entrance profile was measured: v1 = 3 m/s. Calculate the discharge and mean velocity at the outlet profile (see figure below). Determine also type of flow in both conduit profiles (whether the flow is laminar or turbulent) – temperature of water T = 12° C. (use Reynold’s number Re), For laminar flow: Re<2320, For turbulent flow Re>2320, Kinematic viscosity of water of 12°C, v is equal to 1,24 10^-6 m2/s.
The commercial 11 m long rectangular section shown in the figure from a channel made of steel (E=0.045mm), density 860 kg/m3 And oil with a viscosity of 4 cp is 11/10 m3 with a flow rate of /s it flows. According to this; a) Pressure loss in the channel (Pa), b) Load loss (m) c) Calculate the required pump power (W) to meet this pressure loss. 16 cm 36 cm
Starting from Tw find T, 2 1 3 and proof the following equation f and Re using dimensional analysis: Fully Developed Pipe Flow Friction Factor • Tw = func(p, V, µ, D, ɛ) 8 = average roughness of the inside wall of the pipe pVD Re = 8Tw • I-analysis gives II1 = f %3D pV? II2 = Re €/D = roughness factor %3D Il3 D - II1 = func(II2, I3) |f = func(Re, e/D)|
A long pipeline carries 75.0 cfs of water from reservoir 1 to junction J, where it is distributed into pipes 2 and 3 and transported to reservoirs 2 and 3. Determine the surface elevation of reservoir 3, given the following: WS elevation R₁ = 3200 ft R₂ = 3130 ft R3 =? Pipes 1 2 3 Length 8,000 ft 2,000 ft 3,000 ft Use Hazen-William's coefficient of 150 for all pipes. Note: WS- Water surface R - reservoir Diameter 3.0 ft 2.5 ft 2.0 ft
for line Pife i Daen Daimetel omm Q = 1. 6 LI m.n Dhact = 26 Cm Determing %3D BQ m/s m/s (3) oh theo Re at tube length To cm
Please try to solve it within 30 minutes
Dimensions of a hydraulic cylinder are Dsore=178 mm, Dpiston Rod=50 mm. For a 1,6 m/min extracting speed; Determine the supply flow rate (It/min) Q= ? It/min
Q1) What head H is needed in Fig. 3 to produce a discharge of 0.3 m/s? use minor loss coefficient of 0.5 for the entrance and 0.12 for diffusers. Figure 1. Lite beer 5.9.-1.00 0.05 pojse 30 m 210-mm diam Square edge Smooth pipe Fig. 1 60 m 305 mm diam B 450 mm diam 1634
For the duct system, plot required fan head Hrequired (mm of water column) as a function of volume flow rate V. (Lpm). On the same plot, compare available fan head Havailable versus V. , and mark the operating point. Discuss.
Problem 5: Pipe Flow A 10,000 ft P BC 20,000 ft D This semester we worked through several versions of the pipe flow problem sketched above, in which a 3.0 ft diameter pipe is used to convey water from reservoir A (surface elevation 80 ft) to reservoir D (surface elevation 90 ft). In week 14, we considered a specific example with a cast iron pipe (A = 0.00085 ft), flow rate of Q=40 ft³/s, and average velocity of V = 5.66 ft/s. For these conditions, the friction factor was λ = 0.015 and the pump added 86 ft of head. Assume the water temperature is always 60°F. Part A Assuming the pump is 75% efficient and electricity costs 10e/kW.hr, how much will it cost to run this pump for a year? Hint, 1 kW hr = (1000 watts) (1 hr) = (1000 J/s)(3600 s) = 3.6x106 J. Part B Now let us assume we need to double the discharge to Q = 80 ft³/s, but unlike the example in week 13, we are not going to make the false assumption that the friction factor λ is constant. You may, however, assume that the roughness…