Determine the elastic tensile load "F" that acts on mild steel specimen of Diameter 9 mm & Modulus of Elasticity 201 GPa. It is found that the specimen has undergone an extension of 1 mm due to the elastic load "F". Also, determine the length "L" of the specimen, if the strain- induced due to the load "F" on the specimen is 3.6 x 10-³. Solution Cross-sectional Area, A (in mm²): 63.617 One possible correct answer is: 63.617251235193 Tensile Stress, (in N/mm²) = 723.6 One possible correct answer is: 723.6 Tensile Load, (in N) = = 46033.261 One possible correct answer is: 46033.442993786 Length of the Specimen (in mm) 4.366 X One possible correct answer is: 277.77777777778

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Strain energy

The term strain indicates the variation in an object's length, area, and volume when the object is subjected to an external force. The external force may be of normal, shear, moment, torque, etc. The strain in an object depends on the types of external force and cross-section of the object. Mathematically, the evaluation of strain can be obtained with the help of elastic constants.