Determine the displacement, velocity, and acceleration of a mass-spring system with k=1200Nm,m=5kg,x0=0.1m,and v0=5m/s. Note that this question may have more than one answer.

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Chapter1: Units, Trigonometry. And Vectors
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Determine the displacement, velocity, and acceleration of a mass-spring system with k=1200Nm,m=5kg,x0=0.1m,and v0=5m/s.

 

Note that this question may have more than one answer.

 

 

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Can you pls solve according to thsese options

 

x(t) = cos(4√15t) + √5 sin(4√/15t)
12
i(t) = 5cos(4√/15t) — 2√5 sin(4√15t)
ä(t) = -24cos(4√/15t) - 20√/15 sin(4√/15t)
x(t) = 0.1cos(4√/15t) + 0.3227sin(4√/15t)
i(t) = 5cos(4√/15t) - 1.549sin(4√/15t)
ä(t) = -24cos(4√/15t) – 77.46sin(4√/15t)
x(t) = 0.1cos (240t) + 0.3227sin(240t)
i(t) = 5cos (240t) - 1.549sin(240t)
ä(t) = -24cos(240t) – 77.46sin(240t)
r(t) = cos(4√/15t) + sin(4√15t)
i(t) = 20cos(4√/15t) - 15sin(4√/15t)
ä(t) = -40cos(4√/15t) - 80sin(4√/15t)
Not enough information to find the displacement, velocity,
All other options are correct.
Transcribed Image Text:x(t) = cos(4√15t) + √5 sin(4√/15t) 12 i(t) = 5cos(4√/15t) — 2√5 sin(4√15t) ä(t) = -24cos(4√/15t) - 20√/15 sin(4√/15t) x(t) = 0.1cos(4√/15t) + 0.3227sin(4√/15t) i(t) = 5cos(4√/15t) - 1.549sin(4√/15t) ä(t) = -24cos(4√/15t) – 77.46sin(4√/15t) x(t) = 0.1cos (240t) + 0.3227sin(240t) i(t) = 5cos (240t) - 1.549sin(240t) ä(t) = -24cos(240t) – 77.46sin(240t) r(t) = cos(4√/15t) + sin(4√15t) i(t) = 20cos(4√/15t) - 15sin(4√/15t) ä(t) = -40cos(4√/15t) - 80sin(4√/15t) Not enough information to find the displacement, velocity, All other options are correct.
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