n the final section of the lab, the student is asked to investigate the energy distribution of the spring system described previously. The student pulls the mass down an additional 16.116.1 cm from the equilibrium point of 21.521.5 cm when the mass is stationary and allows the system to oscillate. Using the equilibrium point of 21.521.5 cm as the zero point for total potential energy, calculate the velocity and total potential energy for each displacement given and insert the correct answer.
Simple harmonic motion
Simple harmonic motion is a type of periodic motion in which an object undergoes oscillatory motion. The restoring force exerted by the object exhibiting SHM is proportional to the displacement from the equilibrium position. The force is directed towards the mean position. We see many examples of SHM around us, common ones are the motion of a pendulum, spring and vibration of strings in musical instruments, and so on.
Simple Pendulum
A simple pendulum comprises a heavy mass (called bob) attached to one end of the weightless and flexible string.
Oscillation
In Physics, oscillation means a repetitive motion that happens in a variation with respect to time. There is usually a central value, where the object would be at rest. Additionally, there are two or more positions between which the repetitive motion takes place. In mathematics, oscillations can also be described as vibrations. The most common examples of oscillation that is seen in daily lives include the alternating current (AC) or the motion of a moving pendulum.
In the final section of the lab, the student is asked to investigate the energy distribution of the spring system described previously. The student pulls the mass down an additional 16.116.1 cm from the equilibrium point of 21.521.5 cm when the mass is stationary and allows the system to oscillate. Using the equilibrium point of 21.521.5 cm as the zero point for total potential energy, calculate the velocity and total potential energy for each displacement given and insert the correct answer.
![In the final section of the lab, the student is asked to investigate the energy distribution of the spring system described previously. The student pulls the mass down an additional 16.1 cm from the equilibrium point of 21.5 cm when the mass is stationary and allows the system to oscillate. Using the equilibrium point of 21.5 cm as the zero point for total potential energy, calculate the velocity and total potential energy for each displacement given and insert the correct answer.
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**Table:**
| Displacement (cm) from equilibrium | Velocity (m/s) | Total potential energy (J) |
|------------------------------------|----------------|----------------------------|
| 16.1 | 0 | [Blank] |
| 11.8 | 1.09 | [Blank] |
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**Answer Bank:**
- 0.311
- 0.0941
- [Blank]
- 0.175
- 0
- 0.74
Note: The table requires filling in the values for total potential energy using the answer bank.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45a38078-7db9-4eb5-9b9c-df964c9c580e%2Ff498cd21-0734-42b1-8289-93a36b5e4d55%2Fm6blj4_processed.png&w=3840&q=75)
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