A vertical spring is so that it's stretched 1/4 meter when a 1/2 kg mass is attached at the end ofit. Recall that F = ma and Hooke's Law states that F = ky. Use a = g = 9.8 m/s².The mass is pushed downward, stretching the spring a distance of 1/10 m and then set inmotion with an upward velocity of 2 m/s. Assume there is no damping.a) Find the spring constant.b) Write the appropriate initial value problem (differential equation) for this spring.Don't forget to include the initial conditions. Don't solve the equation, just set it up.

Given:mass attached to spring, m = 0.5 kgthe spring streches by d = 0.25 m to attain…

Answered: A vertical spring is so that it's…

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A block with a mass m = 2.5 kg is pushed into an ideal spring whose spring constant is k = 4520 N/m. The spring is compressed x = 0.066 m and released. After losing contact with the spring, the block slides a distance of d = 2.25 m across the floor before coming to rest. a. Write an expression for the coefficient of kinetic friction between the block and the floor using the symbols given in the problem statement and g (the acceleration due to gravity). (Do not neglect the work done by friction while the block is still in contact with the spring.)
K Question 13 of 32 A spring hangs from the ceiling with an unstretched length of xo = 0.99 m. A m¡ = 9.1 kg block is hung from the %3D spring, causing the spring to stretch to a length X = 1.18 m. Find the length x2 of the spring when a m2 = 3.3 kg block is hung from the spring. For both cases, all vibrations of the spring are allowed to settle down before any measurements are made. m2 X2 = %3D 0.04 m m,
Refer to the picture below
Use g = 10m/s/s
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