Determine the design flexural strength in ft kips of a W10X26 of A242 (Fy = 50ksi) steel subject to a. Continuous lateral support. Blank 1 b. An unbraced length of 10 ft with Cb = 1.0. Blank 2 c. An unbraced length of 20 ft with Cb = 1.0. Blank 3 Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer A = d= tw= bf= tf = #T T= k= k1 = gage = rt= d/Af= x= Sx= Ix= ly= Sy= ry= Zx = Zy= J= Cw= a = Wno = Sw= Qf= Qw= W10x26 7.61 10.300 0.260 5.770 0.440 8-1/4 0.7400 0.6875 2-3/4 1.540 4.07 144.00 27.90 4.350 14.10 4.89 1.360 31.30 7.50 0.40 345 47.14 14.30 9.05 5.99 15.50 in.^2 in. in. in. in. in. in. in. in. in. in.4 in.43 in. in 14 in.43 in. in.^3 in.43 in.4 in.46 in. in.42 in.4 in.43 in.43 :

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Determine the design flexural strength in ft kips of a W10X26 of A242 (Fy = 50ksi) steel subject to
a. Continuous lateral support. Blank 1
b. An unbraced length of 10 ft with Cb = 1.0. Blank 2
C. An unbraced length of 20 ft with Cb = 1.0. Blank 3
W10x26
...
A =
7.61
in.^2
d =
10.300
in.
tw =
0.260
in.
bf =
5.770
in.
tf =
0.440
in.
T =
8-1/4
in.
0.7400
k =
k1 =
in.
0.6875
in.
gage =
2-3/4
in.
rt =
1.540
in.
d/Af =
4.07
Ix =
144.00
in.14
Sx =
27.90
in.^3
rx =
4.350
in.
ly =|
Sy =
ry =
Zx =
14.10
in.^4
4.89
in.13
1.360
in.
31.30
in.^3
Zy =
7.50
in 43
J =
0.40
in.^4
in. ^6
Cw =
345
a =
47.14
in.
Wno =
14.30
in.^2
Sw =
9.05
in. ^4
Qf =
5.99
in.43
Qw =
15.50
in.43
Blank 1 Add your answer
Blank 2 Add your answer
Blank 3
Add your answer
Transcribed Image Text:Determine the design flexural strength in ft kips of a W10X26 of A242 (Fy = 50ksi) steel subject to a. Continuous lateral support. Blank 1 b. An unbraced length of 10 ft with Cb = 1.0. Blank 2 C. An unbraced length of 20 ft with Cb = 1.0. Blank 3 W10x26 ... A = 7.61 in.^2 d = 10.300 in. tw = 0.260 in. bf = 5.770 in. tf = 0.440 in. T = 8-1/4 in. 0.7400 k = k1 = in. 0.6875 in. gage = 2-3/4 in. rt = 1.540 in. d/Af = 4.07 Ix = 144.00 in.14 Sx = 27.90 in.^3 rx = 4.350 in. ly =| Sy = ry = Zx = 14.10 in.^4 4.89 in.13 1.360 in. 31.30 in.^3 Zy = 7.50 in 43 J = 0.40 in.^4 in. ^6 Cw = 345 a = 47.14 in. Wno = 14.30 in.^2 Sw = 9.05 in. ^4 Qf = 5.99 in.43 Qw = 15.50 in.43 Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer
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