A W12 x 79 of A992 Steel.Check if the section is compact.Check the adequacy both LRFD and ASD. Use AISC. D= 265kL = 130k18'A992 STEEL: Fy = 50 ksi and Fu = 65 ksi W12x79A =23.20in.^212.400in.tw0.470in.bf =12.100in.tf =0.735in.T =9-1/8in.k =1.3300lin.k1 =1.0625in.(2) 5-1/2 (2)in.gage =in.rt =3.310d/Af =1.39Ix =662.00in. ^4Sx =107.00in. ^3rx5.340in.ly =Sy =216.00in. ^435.80in.^3ry =3.050in.IIく d

Answered: Image /qna-images/answer/69f3359d-9ca6-483a-9152-0cddfdee8905.jpg

Answered: D = 265k L = 130k 18'

Engineering

Civil Engineering

D = 265k L = 130k 18'

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Compute its design strength based on rupture in kiloNewtons..* 412 485 453 389 438 This is a…

A: Given, Fu = 400 MPa Fy = 248 MPa D = 16 mm Dh = D + 2

Q: The welded girder shown in the accompanying illustration has an external shear VD = 300 k and VL =…

A: VD=300 kVL=350 k

Q: ASSIGNMENT #5 BIAXIAL BENDING Problem: Check the beam shown for compliance with the NSCP…

A: Section: W410 x 100 A992 steel fy = 345 MPa DL = 30% LL = 70%

Q: 1.A tension member is 25 mm thick plate as shown. The bolts are 20 mm. diameter high-strength bolts.…

A: Plate 130 mm x 25 mmbolt diameter, db = 20 mmA36 grade of steel:fy = 250 MPafy = 400 MPaTo find:a)…

Q: A W 14 x 142 is used as a column having length of 9 m long. It is hinged at the upper end and fixed…

Q: connecte lameter bolts in each flange, as sho fFy 448 MPa, and Ae = 0.90An, compute the following.…

A: Given: C12x30 member 25 mm dia bolts fy=345 MPa, fu= 448 MPa Ae= 0.9 An

Q: 4.3-2 Compute the nominal axial compressive strength of the member shown in Figure P4.3-2. Use AISC…

Q: 1.) Determine the area of the Composite section 2.) Determine the center of gravity of the…

Q: Determine the available strength of the compression member shown in Figure , in each of the…

A: Given data HSS 10×6×12 section Length, L=15ft=180in. ASTM A500, Grade C Steel Fy = 50 ksi Ag = 13.5…

Q: For axially loaded steel column, how could you determine that your section is safe? In case of…

A: In order to determine the safety of the steel column section. The stress available in the section is…

Q: 1.10-4 Lateral bracing for an elevated pedestrian walkway is shown in the figure part a. The…

Q: Determine whether the compression member shown in Figure is adequate to support the given service…

A: Given, D=110 kips L=280 kips

Q: Pe Po Pp P. If lateral support is provided at both ends, and at the load points, select the lightest…

Q: USE NSCP 2015 A W460X177 is used as a compression member with one end fixed and the other end fixed…

A: Given values: Section used: W 460*177 Length, L =3657 mm One end fixed and other end fixed against…

Q: 4. An A992 WF steel section is used for the tension member shown in the figure. The bolts are 20mm…

A: Section W14x68bolt diameter, db = 20 mmA992 grade of steel:fy = 345 MPafu = 450 MPaTo find:a. The…

Q: 1- A structural analysis was done for the steel section whose shape and characteristics are shown…

Q: 2. Select the most economical (lightest) W sections of A572 Gr. 50 steel. The beam is braced at ends…

A: A572 Gr. 50 steelLb = 15'WDL = 3 klfWLL = 1 klf

Q: The beam under the Live and Dead loads is shown below. The steel class is $235. 4.8 A L1 L2 a.)…

A: Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…

Q: If the tension member of is welded as shown, determine the effective area 5450⁰ 1 L 150x150x12 +…

Q: 4. An A992 WF steel section is used for the tension member shown in the figure. The bolts are 20mm…

A: A W16x67 is given , we need to find out a. The nominal strength based on gross section yielding.b.…

Q: The truss shown is composed of steel sections. If the 2L150 x 90 x 8 A36 steel section was used in…

Q: choose the W section of 50 ksi steel

Q: loads shown. Does this member have enough strength Assume that . a) Per LRFD b) Per ASD

A: For grade A 36,Dead load =95 kipsLive load =9 kipsNeed to findDoes member have enough strength.(a)…

Q: A W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset…

A: Answer Calculation of yielding capacity of the section based on LRFD We know that yielding capacity…

Q: D=95k O O o O L = 9k PL ½x 8

A: Calculate gross area and net area:

Q: An angle L5x5x% tension member of A36 steel is connected to a gusset plate with six 3/4-inch…

A: Tension member L5x5x5/8A36 steel.Bolt diameter, db = 3/4 in6 bolts spaced 3 inThe length of the…

Q: 2. The composite section is made up of 5"x3"x1/2" and 6"x4"x1/2" angle bars on 1"x 12" and 1.5"x16"…

A: Given Data:section made up of = 5''×3''×1''2 and 6''×4''×12''…

Q: tion for compliance with the AISC Spec strength is controlled by the bearing de a. Use LRFD. b. Use…

Q: Plate 10 4 in. Plate x8 <8

Q: Sidesway is prevented for the beam-column shown in the Fig. P11-17. If the first-order momen ts…

A: L = 12 ftPDL = 60 kPLL = 70 kMDx = 12 ft-kMLx = 15 ft-k

Q: A steel plate (called a cover plate) having cross-sectional dimensions W2 5.0 in. x 0.4 in. is…

A: The given data is shown below: W2=5 in.×0.4 in.W1=12 in.×87 in.

Q: Compute the maximum acceptable tensile SERVICE LOAD that may act on a single tee section that is…

A: Answer In order to calculate the minimum acceptable tensile service load we need to first find the…

Q: Governing Ultimate Tensile Capacity based on Yielding of gross section

A: Gross area Ag=11.2 in2Yield stress Fy=50 ksiUltiate stress Fu=65 ksiy¯=3 inLength of weld L=12…

Q: PROBLEM 4: The beam shown the figure below is a W16x31 of A992 steel and has continuous lat- eral…

Q: HOMEWORK-1 3m For the truss shown in the figure; Design members 1-2 and 2-3 assuming that out of…

A: a.given that, F=4000kg AB=4m AC=3m BC=42+32=5 m so, we have to calculate the bar force.…

Q: The A36 tension member is connected with 6- 16 mm diameter bolt. The member is made of Plate PL…

Q: A circular hollow section (CHS) member is to be used as an internal column in a multi- storey…

A: Solution Take design load= 2100 kN Effective length= l= 6.5 m( Both end pinned connection)

Q: Problem 1: Hanger in Tension with Block Shear The W12 X 53 tension member shown below has two rows…

A: Given: db = 1 in Fy = 50 ksi Fu = 65 ksi section properties: W 12 x 53 Ag=15.6 in2 d = 12.1 in tw =…

Question

100%

A W12 x 79 of A992 Steel.

Check if the section is compact.
Check the adequacy both LRFD and ASD. Use AISC.

D= 265k
L = 130k
18'
A992 STEEL: Fy = 50 ksi and Fu = 65 ksi

W12x79
A =
23.20
in.^2
12.400
in.
tw
0.470
in.
bf =
12.100
in.
tf =
0.735
in.
T =
9-1/8
in.
k =
1.3300
lin.
k1 =
1.0625
in.
(2) 5-1/2 (2)
in.
gage =
in.
rt =
3.310
d/Af =
1.39
Ix =
662.00
in. ^4
Sx =
107.00
in. ^3
rx
5.340
in.
ly =
Sy =
216.00
in. ^4
35.80
in.^3
ry =
3.050
in.
II
く d

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Please double Check your final answer. Civil Engineering- Steel Design
For the welded angle, determine the maximum tensile strength. Assume A992 grade steel. 6" 4" Pu L5 × 5 × ¾
A steel plate (called a cover plate) having cross-sectional dimensions W2 8.0 in. x 0.7 in. is welded along the full length of the bottom flange of a W, 12.0 in. x 14.0 in. wide-flange beam (see the figure, which shows the beam cross section). I W2 cover plate What is the percent increase in the smaller section modulus (as compared to the wide-flange beam alone)? Round your answer to two decimal places. % in smaller section modulus =|
With reference to the NSCP 2015, choose the correct statement: For design of flexure members, tension-controlled section is: Select the correct response: when the tensilę steel strain is greater than or equal to 0.005 when the tensile steel strain is greater than or equal to 0.004 when the tensile steel strain is greater than or equal to 0.003 when the tensile steel strain is greater than or equal to the tensile yield strain / DreviOUS
A plate is used as a tension member, to carry a deadload = 300 KN and live load of 260 KN. Steel used is A36, Fy= 248 MPa, Fu = 400 MPa. If the width of the tension plate is 210 mm, determine: a) The thickness of the plate based on NSCP 2015 ASD, bult used is M20.------ b) The thickness of plate based on NSCP 2015 LRFD. Bolt used is M20.-------- I M20 bolts- 210 mm -Tension Plate
An A36 W14X605 simply supported steel beam with span “L” carries a concentrated service liveload “PLL” at midspan. The beam is laterally supported at supports and its midspan. Consider its beam selfweight to be its service deadload, “w” (use ASEP steel manual for selfweight, w and other section properties). a. Check for compactness of the given section? b. In checking section's compactness, calculate the upper limit for compact flange category? c. In checking section's compactness, calculate the upper limit for non-compact web category?
Q4/ Give reason PLLA and PDLA are more common used for load-bearing applications?
A W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset plate by 3/4 inch boltas shown below. Use A36 steel with Fy-36 ksi and Fu=58 ksi Determine the Yielding Capacity of the section based on LRFD (kips) Determine the Tensile Rupture capacity of the section based on LRFD Determine the Demand to Governing Capacity Ratio (based on yielding and rupture only) if the Demand load carried by the section are DL=200 kips LL=400 kips use LRFD Properties and Dimension Ag=35.30 in^2 x = 6.24 in ry= 3.74 in d=14.5 in tf=0.94 in bf=14.7 in tw=0.59 in k=1.54 d=14.5 Y k1=1.5 bf=14.7 tf-0.94 X -tw=0.59 H
7. Determine the design tensile strength of the plate (200 x 10 mm) connected to 12 mm thick gusset, using 24 mm bolts as shown below. Use A572M Grade 345 steel materials. 200 40 50 40 30 30 30 30 40
A PL3/8"X6" tension member is welded to a gusset plate as shown in the figure. The steel specification is ASTM A36. Assume that and compute the following: a) The design strength per LRFD b) The design strength per ASD PL ¾ x 6