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Determine the current flowing through R₂, given: R₁ = 20, R₂ = 60, and I₁ = 13 A (Round the FINAL answer to one decimal place.) E₁

Determine the current flowing through R₂, given: R₁ = 20, R₂ = 60, and I₁ = 13 A (Round the FINAL answer to one decimal place.) E₁

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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**Problem Statement:** Determine the current flowing through \( R_2 \), given: - \( R_1 = 2 \, \Omega \) - \( R_2 = 6 \, \Omega \) - \( I_1 = 13 \, \text{A} \) (Round the FINAL answer to one decimal place.) **Circuit Diagram Explanation:** The circuit diagram illustrates a simple series circuit consisting of a voltage source \( E_T \), two resistors (\( R_1 \) and \( R_2 \)), and an ammeter measuring the current \( I_1 \). The resistors are in series, meaning the same current flows through both resistors. **Approach for Solution:** 1. **Identify Series Connection:** - In a series circuit, the current is the same through all components. Hence, the current through \( R_2 \) is equal to \( I_1 \). 2. **Current Calculation:** - Since \( I_1 = 13 \, \text{A} \), the current flowing through \( R_2 \) is also \( 13 \, \text{A} \). 3. **Final Answer:** - The current flowing through \( R_2 \) is \( 13.0 \, \text{A} \). **Note:** In this problem, the resistances don’t affect the current calculation due to the series connection with a given current \( I_1 \).
Transcribed Image Text:**Problem Statement:** Determine the current flowing through \( R_2 \), given: - \( R_1 = 2 \, \Omega \) - \( R_2 = 6 \, \Omega \) - \( I_1 = 13 \, \text{A} \) (Round the FINAL answer to one decimal place.) **Circuit Diagram Explanation:** The circuit diagram illustrates a simple series circuit consisting of a voltage source \( E_T \), two resistors (\( R_1 \) and \( R_2 \)), and an ammeter measuring the current \( I_1 \). The resistors are in series, meaning the same current flows through both resistors. **Approach for Solution:** 1. **Identify Series Connection:** - In a series circuit, the current is the same through all components. Hence, the current through \( R_2 \) is equal to \( I_1 \). 2. **Current Calculation:** - Since \( I_1 = 13 \, \text{A} \), the current flowing through \( R_2 \) is also \( 13 \, \text{A} \). 3. **Final Answer:** - The current flowing through \( R_2 \) is \( 13.0 \, \text{A} \). **Note:** In this problem, the resistances don’t affect the current calculation due to the series connection with a given current \( I_1 \).
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