Determine the change in energy (in kJ/mol) of the given nuclear fission reaction. 239 Ри 94 Pu + ¿n → Xe + 1 Zr + 3,n 103 Zr + 3,n 54 40 Mass of Pu-239 = 239.052 g/mol; Mass of Xe-134 = 133.905 g/mol; Mass of Zr-103 = 102.926 g/mol Mass of proton = 1.0078 amu; Mass of neutron = 1.0087 amu Speed of light = 3.00 x 10° m/s 1 amu = 1 g/mol = 1.66 x 10-27 kg 1 MeV = 1.60 x 10-13 J Express your answer in scientific notation with 2 decimal places (e.g. 1.23E4, 1.23E-4, -1.23E4, etc.). Do not write the units.

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Determine the change in energy (in kJ/mol) of the given nuclear fission reaction.

 

Mass of Pu-239 = 239.052 g/mol; Mass of Xe-134 = 133.905 g/mol; Mass of Zr-103 = 102.926 g/mol

Mass of proton = 1.0078 amu; Mass of neutron = 1.0087 amu

Speed of light = 3.00 x 108 m/s

1 amu = 1 g/mol = 1.66 x 10-27 kg

1 MeV = 1.60 x 10-13 J

Express your answer in scientific notation with 2 decimal places (e.g. 1.23E4, 1.23E-4, -1.23E4, etc.). Do not write the units.

Determine the change in energy (in kJ/mol) of the given nuclear
fission reaction.
239 Ри
94
Pu + ¿n → Xe + 1 Zr + 3,n
103 Zr + 3,n
54
40
Mass of Pu-239 = 239.052 g/mol; Mass of Xe-134 = 133.905 g/mol; Mass of
Zr-103 = 102.926 g/mol
Mass of proton = 1.0078 amu; Mass of neutron = 1.0087 amu
Speed of light = 3.00 x 10° m/s
1 amu = 1 g/mol = 1.66 x 10-27 kg
1 MeV = 1.60 x 10-13 J
Express your answer in scientific notation with 2 decimal places
(e.g. 1.23E4, 1.23E-4, -1.23E4, etc.). Do not write the units.
Transcribed Image Text:Determine the change in energy (in kJ/mol) of the given nuclear fission reaction. 239 Ри 94 Pu + ¿n → Xe + 1 Zr + 3,n 103 Zr + 3,n 54 40 Mass of Pu-239 = 239.052 g/mol; Mass of Xe-134 = 133.905 g/mol; Mass of Zr-103 = 102.926 g/mol Mass of proton = 1.0078 amu; Mass of neutron = 1.0087 amu Speed of light = 3.00 x 10° m/s 1 amu = 1 g/mol = 1.66 x 10-27 kg 1 MeV = 1.60 x 10-13 J Express your answer in scientific notation with 2 decimal places (e.g. 1.23E4, 1.23E-4, -1.23E4, etc.). Do not write the units.
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