The neutron-induced fission of U-235 produces Ba-140 and Kr-93, along with 3 neutrons. Use the following atomic masses: U-325: 235.04392 amu neutron: 1.00866 amu Ba-140: 139.910581 amu Kr-93: 92.931130 amu If the US needs 1.71 x 1016 kJ of electrical energy every year (for 2018 the value was 1.44 x 1016 kJ), how many kg of U-235 would have to undergo fission to supply this energy? (You can assume 100% efficiency in the conversion of energy from the fission reaction to electricity. This is of course not the case.)
The neutron-induced fission of U-235 produces Ba-140 and Kr-93, along with 3 neutrons.
Use the following
U-325: 235.04392 amu
neutron: 1.00866 amu
Ba-140: 139.910581 amu
Kr-93: 92.931130 amu
If the US needs 1.71 x 1016 kJ of electrical energy every year (for 2018 the value was 1.44 x 1016 kJ), how many kg of U-235 would have to undergo fission to supply this energy? (You can assume 100% efficiency in the conversion of energy from the fission reaction to electricity. This is of course not the case.)
Note: For fun, compare this mass of uranium to the mass of coal that would be required-- for every kg of uranium, you need 4,500 TONS of coal!!
Report your answer without scientific notation (hint: you shouldn't need a ridiculous number of digits to express your answer) and with three significant figures (meaning you will have to round it!)
Trending now
This is a popular solution!
Step by step
Solved in 4 steps
