Determine concentration of OH" in a 0.60 M solution of HNO2 (Ka = 7.1 x 10-4). 1 2 3 Based on the given values, set up ICE table in order to determine the unknown. HNO2(aq)+ H20(1) =H;0*(aq) + NO, (aq) Initial (M) Change (M) Equilibrium (M) 5 RESET 0.60 7.1 x 10-4 1.4 x 10-11 0.30 +x -X +2x -2x 0.60 + x 0.60 - x 0.60 + 2x 0.020 - 2x 1.4 × 10-1" + x 1.4 x 10-11 - |1.4 x 10-11 + 2х 1.4 x 10-11 - 2x
Determine concentration of OH" in a 0.60 M solution of HNO2 (Ka = 7.1 x 10-4). 1 2 3 Based on the given values, set up ICE table in order to determine the unknown. HNO2(aq)+ H20(1) =H;0*(aq) + NO, (aq) Initial (M) Change (M) Equilibrium (M) 5 RESET 0.60 7.1 x 10-4 1.4 x 10-11 0.30 +x -X +2x -2x 0.60 + x 0.60 - x 0.60 + 2x 0.020 - 2x 1.4 × 10-1" + x 1.4 x 10-11 - |1.4 x 10-11 + 2х 1.4 x 10-11 - 2x
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![8:43 1
5G E
Question 13 of 25
Submit
Determine concentration of OH in a 0.60 M
solution of HNO2 (Ka = 7.1 x 10-4).
1
2
3
Based on the given values, set up ICE table in
order to determine the unknown.
HNO2(aq)+ H20(1) =H;O*(aq) + NO, (aq)
Initial (M)
Change (M)
Equilibrium
(M)
5 RESET
0.60
7.1 × 10-4
1.4 x 10-11
0.30
+x
-X
+2x
-2x
0.60 + x
0.60 - x
0.60 + 2x
0.020 - 2x
1.4 × 10-1" + x
1.4 × 10-11 - x
1.4 x 10-11 + 2х
1.4 x 10-11 - 2x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F339c79e1-db01-425a-979b-850e87e97e48%2Ff7463480-cd4d-4d4e-bf1f-78391a1cc340%2Fckmezbj_processed.png&w=3840&q=75)
Transcribed Image Text:8:43 1
5G E
Question 13 of 25
Submit
Determine concentration of OH in a 0.60 M
solution of HNO2 (Ka = 7.1 x 10-4).
1
2
3
Based on the given values, set up ICE table in
order to determine the unknown.
HNO2(aq)+ H20(1) =H;O*(aq) + NO, (aq)
Initial (M)
Change (M)
Equilibrium
(M)
5 RESET
0.60
7.1 × 10-4
1.4 x 10-11
0.30
+x
-X
+2x
-2x
0.60 + x
0.60 - x
0.60 + 2x
0.020 - 2x
1.4 × 10-1" + x
1.4 × 10-11 - x
1.4 x 10-11 + 2х
1.4 x 10-11 - 2x
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