Given the two reactions 1. H2S(aq) = HS (aq) + H+(aq), K1 = 9.15×10-8, and 2. HS (aq) = S²-(aq) + H+ (aq), K2 = 1.39×10-19, what is the equilibrium constant Kfinal for the following reaction? S2-(aq) + 2H+(aq) = H2S(aq)
Given the two reactions 1. H2S(aq) = HS (aq) + H+(aq), K1 = 9.15×10-8, and 2. HS (aq) = S²-(aq) + H+ (aq), K2 = 1.39×10-19, what is the equilibrium constant Kfinal for the following reaction? S2-(aq) + 2H+(aq) = H2S(aq)
Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter5: Introduction To Chemical Equilibrium
Section: Chapter Questions
Problem 5.31E
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Question
![Given the two reactions
1. H2 S(aq) = HS (aq) + H†(aq), K1 = 9.15×10-8, and
2. HS (aq) = S²-(aq) + H+(aq), K2 = 1.39×10-19,
what is the equilibrium constant Kfinal for the following reaction?
s2- (аq) + 2H* (аq)
= H2S(aq)
Enter your answer numerically.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F73c06fe2-676c-4691-b9a6-3dd730b03b91%2Fc7feb996-0ce3-4397-8fea-d8886399b64f%2Fsc7f8n_processed.png&w=3840&q=75)
Transcribed Image Text:Given the two reactions
1. H2 S(aq) = HS (aq) + H†(aq), K1 = 9.15×10-8, and
2. HS (aq) = S²-(aq) + H+(aq), K2 = 1.39×10-19,
what is the equilibrium constant Kfinal for the following reaction?
s2- (аq) + 2H* (аq)
= H2S(aq)
Enter your answer numerically.
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