Determine (a) the output power. and (b) the efficiency of a three-phase, 400 V induction motor running on load with a fractional slip of 0.04 and taking a current of 50 A at a power- factor of 0.86. When running light, without any load, at 400 V, the motor has an input current of 15 A and the power taken is 2000 W, of which 650 W represents the friction-and-windage loss. The resistance between any two terminals of the delta-connected winding is 0.333 N. Do not ignore the stator impedance and assume that when the motor is running light, the rotor current is negligible.

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Determine
(a) the output power.
and
(b) the efficiency
of a three-phase, 400 V induction motor running on load with a fractional slip of 0.04 and taking a current of 50 A at a power-
factor of 0.86. When running light, without any load, at 400 V, the motor has an input current of 15 A and the power taken is 2000
W, of which 650 W represents the friction-and-windage loss. The resistance between any two terminals of the delta-connected
winding is 0.333 N. Do not ignore the stator impedance and assume that when the motor is running light, the rotor current is
negligible.
Transcribed Image Text:Determine (a) the output power. and (b) the efficiency of a three-phase, 400 V induction motor running on load with a fractional slip of 0.04 and taking a current of 50 A at a power- factor of 0.86. When running light, without any load, at 400 V, the motor has an input current of 15 A and the power taken is 2000 W, of which 650 W represents the friction-and-windage loss. The resistance between any two terminals of the delta-connected winding is 0.333 N. Do not ignore the stator impedance and assume that when the motor is running light, the rotor current is negligible.
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