Determine (a) the output power. and (b) the efficiency of a three-phase, 400 V induction motor running on load with a fractional slip of 0.04 and taking a current of 50 A at a power- factor of 0.86. When running light, without any load, at 400 V, the motor has an input current of 15 A and the power taken is 2000 W, of which 650 W represents the friction-and-windage loss. The resistance between any two terminals of the delta-connected winding is 0.333 N. Do not ignore the stator impedance and assume that when the motor is running light, the rotor current is negligible.

Determine (a) the output power. and (b) the efficiency of a three-phase, 400 V induction motor running on load with a fractional slip of 0.04 and taking a current of 50 A at a power- factor of 0.86. When running light, without any load, at 400 V, the motor has an input current of 15 A and the power taken is 2000 W, of which 650 W represents the friction-and-windage loss. The resistance between any two terminals of the delta-connected winding is 0.333 N. Do not ignore the stator impedance and assume that when the motor is running light, the rotor current is negligible.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

2. A 250 kVA, 480 V, 50 Hz, delta-connected alternator with a rated field current of 5 A was tested and the following test data were obtained: • Open circuit terminal voltage from OC test data is 540 V at the rated IF. • Short circuit current from SC test data is 300 A at the rated IF. • A dc current of 20A is flowing through any two stator armature terminals, when a DC voltage of 10 V was applied to two of the terminals. Evaluate the following from above tests data the armature resistance, the approximate synchronous reactance and voltage regulation at rated load and 0.7 pf lead.
A DC motor has an internal resistance of 70. This motor has a no load speed of 3912rpm at 20V. This motor is now connected to a voltage divider as shown in the figure, where R1 and R2 are both 1840. Vs is 20V. What is the new no load speed of the motor? Give your answer in rpm. Numerical value only, no units required. + R₁ R₂ Vo Motor
Can you solve the question ?
A 3-phase 50 Hz I.M. has a rated torque = 16.7 N.M and maximum torque = 40.5 N.M. If its rated speed = 910 R.P.M, the speed at :maximum torque will be R.P.M 578.280 R.P.M 421.640 R.P.M 590.160 None O
3 decimal places
answer all parts please
A 400 V, 50 Hz 30 hp, three-phase induction motor is drawing 50 A current at 0.8 power factor lagging. The stator and rotor copper losses are 1.5 kW and 900 W respectively. The friction and windage losses are 1050 W and the core losses are 1200 W. The air-gap power of the motor will be
A 6-pole, 50-Hz, 3-φ induction motor is running at 950 rpm and has rotor Copper loss of 5 kW. Its rotor input is ......kW. 100 10 95 5.3
A240 V d.c. series motor takes 40 A when giving its rated output at (500 r.p.m.its total resistance is 0.32.Find what resistance must be added to obtain rated torque i) At starting
In a 3-phase, 4-pole induction motor, The power crossing the air gap of a 60 Hz is 42.6 kW, and the power converted from electrical to mechanical form in the motor is 39.6 kW. If the total mechanical losses are 1000 W, find the load torque of this motor? Select one: O a. None O b. Tload = 208.4 N.m. O c. Tjoad = 232.6 N.m. O d. Tjoad = 220.3 N.m. Clear my choice