Design ESAL = 5 x 106  Initial serviceability index = 3.5  Terminal serviceability =  2.5 Standard deviation = 0.5 Reliable = 90%

Structural Analysis
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Chapter2: Loads On Structures
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Given:

Design ESAL = 5 x 106 

Initial serviceability index = 3.5 

Terminal serviceability =  2.5

Standard deviation = 0.5

Reliable = 90% 

2] Determine the Structural Number (SN) for a flexible pavement that will be supported by
the following subgrade, base, subbase:
CBRbase
CBRsubbase
CBRsubgrade
Mr asphalt (68 deg. F) = 450,000 psi
100%
25%
a2=0.14
a3=0.10
use Mroadbed soil = 1500 * CBR
a1=0.45
6%
The pavement must be of the following characteristics:
90% Reliable will serve a total load of 5 x 106 ESALS
Standard deviation of 0.5
Initial and terminal serviceability of 3.5 and 2.5, respectively.
Determine also the thicknesses of surface material, base, and subbase. (m2 = 0.6 m3
= 0.8) that would "fit" the SN. Thicknesses of the courses are: {asphalt concrete,
base, subbase} = {D1, 2.5*D1, 2*D1} units: inches
Screenshot (or take a picture of) your use of flexible pavement nomograph.
Transcribed Image Text:2] Determine the Structural Number (SN) for a flexible pavement that will be supported by the following subgrade, base, subbase: CBRbase CBRsubbase CBRsubgrade Mr asphalt (68 deg. F) = 450,000 psi 100% 25% a2=0.14 a3=0.10 use Mroadbed soil = 1500 * CBR a1=0.45 6% The pavement must be of the following characteristics: 90% Reliable will serve a total load of 5 x 106 ESALS Standard deviation of 0.5 Initial and terminal serviceability of 3.5 and 2.5, respectively. Determine also the thicknesses of surface material, base, and subbase. (m2 = 0.6 m3 = 0.8) that would "fit" the SN. Thicknesses of the courses are: {asphalt concrete, base, subbase} = {D1, 2.5*D1, 2*D1} units: inches Screenshot (or take a picture of) your use of flexible pavement nomograph.
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