Design a class A power amplifier that will operate from a DC supply of + 15 V with an approximate voltage gain of 50. The quiescent collector current should be approximately 500 mA, and the total DC current from the supply should not exceed 750 mA. The output power must be at least 1 W. Ic (max) = VCECZ BC= VCEQ Rc IC(max) Iccmax)= Idc=750mA BC= 7.5% = 1052 750mA Vc = Vcc - ICRC I 503 mA approximatly Vc: 15- (503x10³×10) Vc=9.97v VCE: VC-VE VE-NC-NCE =9.97-7.53 = 2.44√ RE: VE- 2.47 = 4.850 Iε 503x10' BE:VB-VE NB: VEB+VE=0.7+2.44 VB=3.14 Let R1-68 VB: VC Ri+ R2= 18.0032 AV: Vout. Vin Re Re Re: Rc = 10 Re: RE₁+ ré 50= 10 RE1+.25 Rε 1:0.15 RET: RE1+ REZ 5031A RE: 4.850-0.15 RE₂ = 4.700852 Pout: 0.5 (503mA) (10) Pout 1.265 watt 71

Design a class A power amplifier that will operate from a DC supply of + 15 V with an approximate voltage gain of 50. The quiescent collector current should be approximately 500 mA, and the total DC current from the supply should not exceed 750 mA. The output power must be at least 1 W. Ic (max) = VCECZ BC= VCEQ Rc IC(max) Iccmax)= Idc=750mA BC= 7.5% = 1052 750mA Vc = Vcc - ICRC I 503 mA approximatly Vc: 15- (503x10³×10) Vc=9.97v VCE: VC-VE VE-NC-NCE =9.97-7.53 = 2.44√ RE: VE- 2.47 = 4.850 Iε 503x10' BE:VB-VE NB: VEB+VE=0.7+2.44 VB=3.14 Let R1-68 VB: VC Ri+ R2= 18.0032 AV: Vout. Vin Re Re Re: Rc = 10 Re: RE₁+ ré 50= 10 RE1+.25 Rε 1:0.15 RET: RE1+ REZ 5031A RE: 4.850-0.15 RE₂ = 4.700852 Pout: 0.5 (503mA) (10) Pout 1.265 watt 71

EBK ELECTRICAL WIRING RESIDENTIAL

19th Edition

ISBN:9781337516549

Author:Simmons

Publisher:Simmons

Chapter25: Television, Telephone, And Low-voltage Signal Systems

Section25.1: Television Circuit

Problem 5R: From a cost standpoint, which system is more economical to install: a master amplifier distribution...

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