Design a class A power amplifier that will operate from a DC supply of + 15 V with an approximate voltage gain of 50. The quiescent collector current should be approximately 500 mA, and the total DC current from the supply should not exceed 750 mA. The output power must be at least 1 W. Ic (max) = VCECZ BC= VCEQ Rc IC(max) Iccmax)= Idc=750mA BC= 7.5% = 1052 750mA Vc = Vcc - ICRC I 503 mA approximatly Vc: 15- (503x10³×10) Vc=9.97v VCE: VC-VE VE-NC-NCE =9.97-7.53 = 2.44√ RE: VE- 2.47 = 4.850 Iε 503x10' BE:VB-VE NB: VEB+VE=0.7+2.44 VB=3.14 Let R1-68 VB: VC Ri+ R2= 18.0032 AV: Vout. Vin Re Re Re: Rc = 10 Re: RE₁+ ré 50= 10 RE1+.25 Rε 1:0.15 RET: RE1+ REZ 5031A RE: 4.850-0.15 RE₂ = 4.700852 Pout: 0.5 (503mA) (10) Pout 1.265 watt 71
Design a class A power amplifier that will operate from a DC supply of + 15 V with an approximate voltage gain of 50. The quiescent collector current should be approximately 500 mA, and the total DC current from the supply should not exceed 750 mA. The output power must be at least 1 W. Ic (max) = VCECZ BC= VCEQ Rc IC(max) Iccmax)= Idc=750mA BC= 7.5% = 1052 750mA Vc = Vcc - ICRC I 503 mA approximatly Vc: 15- (503x10³×10) Vc=9.97v VCE: VC-VE VE-NC-NCE =9.97-7.53 = 2.44√ RE: VE- 2.47 = 4.850 Iε 503x10' BE:VB-VE NB: VEB+VE=0.7+2.44 VB=3.14 Let R1-68 VB: VC Ri+ R2= 18.0032 AV: Vout. Vin Re Re Re: Rc = 10 Re: RE₁+ ré 50= 10 RE1+.25 Rε 1:0.15 RET: RE1+ REZ 5031A RE: 4.850-0.15 RE₂ = 4.700852 Pout: 0.5 (503mA) (10) Pout 1.265 watt 71
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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This question and its solution. Is the solution correct? If the solution is correct, assume that let R2 = 20 and a=500 . If it is wrong, solve it in your own way, away from the sources, and explain to me in detail with a pen and paper, please.

Transcribed Image Text:Design a class A power amplifier that will operate from a DC supply of + 15 V
with an approximate voltage gain of 50. The quiescent collector current should
be approximately 500 mA, and the total DC current from the supply should not
exceed 750 mA. The output power must be at least 1 W.
Ic (max) = VCECZ
BC= VCEQ
Rc
IC(max)
Iccmax)= Idc=750mA
BC= 7.5% = 1052
750mA
Vc = Vcc - ICRC
I 503 mA approximatly
Vc: 15- (503x10³×10)
Vc=9.97v
VCE: VC-VE
VE-NC-NCE
=9.97-7.53
= 2.44√
RE: VE- 2.47 = 4.850
Iε
503x10'
BE:VB-VE
NB: VEB+VE=0.7+2.44
VB=3.14
Let R1-68
VB: VC
Ri+
R2= 18.0032
AV: Vout.
Vin
Re
Re
Re: Rc = 10
Re: RE₁+ ré
50=
10
RE1+.25
Rε 1:0.15
RET: RE1+ REZ
5031A
RE: 4.850-0.15
RE₂ = 4.700852
Pout: 0.5 (503mA) (10)
Pout 1.265 watt 71
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