def increment(x):return x + 1def decrement(x):return x - 1def double(x):return x * 2def apply_n(f, x, n):"""Apply function f to x n times.>>> apply_n (increment, 2, 10)125, 8)apply_n(decrement,>>> apply_n(double, 7, 3)56>>>-3"*** YOUR CODE HERE ***" def square(x):return x * Xdef halve(x):return x // 2def twice(f,x):"""Apply f to the result of applying f to x>>> twice (square,3)81>>> twice (square, 4)256>>> twice (halve, 32)8>>> twice (halve, 80)20*** YOUR CODE HERE ***"

The approach is to check the value of variable f. Use if cases to check the value of f and then…

def increment(x): return x + 1 def decrement(x): return x - 1 def double(x): return x * 2 def apply_n (f, x, n): """Apply function f to x n times. >>>apply_n (increment, 2, 10) >>>apply_n (decrement, 5, 8) >>>apply_n(double, 7, 3) 12 -3 56 " YOUR CODE HERE ***

def increment(x): return x + 1 def decrement(x): return x - 1 def double(x): return x * 2 def apply_n (f, x, n): """Apply function f to x n times. >>>apply_n (increment, 2, 10) >>>apply_n (decrement, 5, 8) >>>apply_n(double, 7, 3) 12 -3 56 " YOUR CODE HERE ***

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

def increment(x):
return x + 1
def decrement(x):
return x - 1
def double(x):
return x * 2
def apply_n(f, x, n):
"""Apply function f to x n times.
>>> apply_n (increment, 2, 10)
12
5, 8)
apply_n(decrement,
>>> apply_n(double, 7, 3)
56
>>>
-3
"*** YOUR CODE HERE ***"

def square(x):
return x * X
def halve(x):
return x // 2
def twice(f,x):
"""Apply f to the result of applying f to x
>>> twice (square,3)
81
>>> twice (square, 4)
256
>>> twice (halve, 32)
8
>>> twice (halve, 80)
20
*** YOUR CODE HERE ***"

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def square(x): return x * X def halve(x): return x // 2 def twice(f,x): """Apply f to the result of applying f to x >>> twice (square,3) 81 >>> twice (square, 4) 256 >>> twice (halve, 32) 8 >>> twice (halve, 80) 20 *** YOUR CODE HERE ***"