def square(x):return x * Xdef halve(x):return x // 2def twice(f,x):"""Apply f to the result of applying f to x>>> twice (square,3)81>>> twice (square, 4)256>>> twice (halve, 32)8>>> twice (halve, 80)20*** YOUR CODE HERE ***" def increment(x):return x + 1def decrement(x):return x - 1def double(x):return x * 2def apply_n(f, x, n):"""Apply function f to x n times.>>> apply_n (increment, 2, 10)125, 8)apply_n(decrement,>>> apply_n(double, 7, 3)56>>>-3"*** YOUR CODE HERE ***"

Answered: def square (x): return x * X def halve…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Related questions

Question

def square(x):
return x * X
def halve(x):
return x // 2
def twice(f,x):
"""Apply f to the result of applying f to x
>>> twice (square,3)
81
>>> twice (square, 4)
256
>>> twice (halve, 32)
8
>>> twice (halve, 80)
20
*** YOUR CODE HERE ***"

def increment(x):
return x + 1
def decrement(x):
return x - 1
def double(x):
return x * 2
def apply_n(f, x, n):
"""Apply function f to x n times.
>>> apply_n (increment, 2, 10)
12
5, 8)
apply_n(decrement,
>>> apply_n(double, 7, 3)
56
>>>
-3
"*** YOUR CODE HERE ***"

Expert Solution

Step 1

code -

def square(x):
return int(x*x);

def halve(x):
return x//2;

def increment(x):
return x+1;


def decrement(x):
return x-1;

def double(x):
return x*2


def twice(f,x):
return f(f(x))


def apply_n(f,x,n):
for i in range(n):
x=f(x)
return x

print(twice(square,4))
print(apply_n(decrement,5,8))

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