Suppose a, b, and sum are int variables and c is a float variable. What value is assigned to each variable after each statement executes? Suppose a = 9, b = 4, and c = 3.8./ a sum sum = static cast (++a + b) + c; 4 3.8 17 - += c * a;
Suppose a, b, and sum are int variables and c is a float variable. What value is assigned to each variable after each statement executes? Suppose a = 9, b = 4, and c = 3.8./ a sum sum = static cast (++a + b) + c; 4 3.8 17 - += c * a;
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![The problem presents a table with initial values of variables and evaluates them through a series of operations. Here's a breakdown of the scenario:
Variables:
- `a`, `b`, and `sum` are integer variables.
- `c` is a float variable.
Initial Values:
- `a = 9`
- `b = 4`
- `c = 3.8`
A series of operations are performed on these variables, and the values of each are updated after each operation. The table columns represent:
- `a`: Value of the integer variable `a`.
- `b`: Value of the integer variable `b`.
- `c`: Value of the float variable `c`.
- `sum`: Value of the integer variable `sum`.
Operations:
1. **Initial Operation:**
\[
\text{sum} = \text{static\_cast<int>}((++a + b) + c);
\]
- \(\text{a}\) is incremented by 1, making it 10.
- Then, \(a + b = 10 + 4 = 14\).
- Adding \(c = 3.8\) gives \(14 + 3.8 = 17.8\).
- Using `static_cast<int>`, 17.8 is cast to 17.
- Resulting values: \(a = 10\), \(b = 4\), \(c = 3.8\), \(\text{sum} = 17\).
2. **Second Operation:**
\[
b += c \times a;
\]
- \(c \times a = 3.8 \times 10 = 38\).
- Updating \(b\) gives \(b = 4 + 38 = 42\).
- Resulting values: \(a = 10\), \(b = 42\), \(c = 3.8\), \(\text{sum} = 17\).
3. **Third Operation:**
\[
c -= \text{static\_cast<float>}(a-- + 1);
\]
- Since \(a--\) uses the post-decrement operator, \(a\) is used as 10 first, then decremented.
- \(a + 1 = 10 + 1 = 11\](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa01058a6-7004-44e6-9008-71f97b41fb6e%2F1dc5f270-3d8d-4661-a77a-c50e0da5f1f6%2Fhior5aq_processed.png&w=3840&q=75)
Transcribed Image Text:The problem presents a table with initial values of variables and evaluates them through a series of operations. Here's a breakdown of the scenario:
Variables:
- `a`, `b`, and `sum` are integer variables.
- `c` is a float variable.
Initial Values:
- `a = 9`
- `b = 4`
- `c = 3.8`
A series of operations are performed on these variables, and the values of each are updated after each operation. The table columns represent:
- `a`: Value of the integer variable `a`.
- `b`: Value of the integer variable `b`.
- `c`: Value of the float variable `c`.
- `sum`: Value of the integer variable `sum`.
Operations:
1. **Initial Operation:**
\[
\text{sum} = \text{static\_cast<int>}((++a + b) + c);
\]
- \(\text{a}\) is incremented by 1, making it 10.
- Then, \(a + b = 10 + 4 = 14\).
- Adding \(c = 3.8\) gives \(14 + 3.8 = 17.8\).
- Using `static_cast<int>`, 17.8 is cast to 17.
- Resulting values: \(a = 10\), \(b = 4\), \(c = 3.8\), \(\text{sum} = 17\).
2. **Second Operation:**
\[
b += c \times a;
\]
- \(c \times a = 3.8 \times 10 = 38\).
- Updating \(b\) gives \(b = 4 + 38 = 42\).
- Resulting values: \(a = 10\), \(b = 42\), \(c = 3.8\), \(\text{sum} = 17\).
3. **Third Operation:**
\[
c -= \text{static\_cast<float>}(a-- + 1);
\]
- Since \(a--\) uses the post-decrement operator, \(a\) is used as 10 first, then decremented.
- \(a + 1 = 10 + 1 = 11\
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