def bonus (num, bon) : for i in range (len (num)) : def main (): bon = 50 print('The bonus is added to all employees: ', Drag and drop the appropriate statement to complete the above code that adds bonus to list of salaries of employees and the output is as The bonus is added to all employees: [1390, 915, 395, 740] return salaries bonus() return num salaries = [1340, 865, 345, 690] bonus(bon) num[i] += bon main() bon bonus(salaries, bon) num[i] *= bon salaries (1340, 865, 345, 690)

def bonus (num, bon) : for i in range (len (num)) : def main (): bon = 50 print('The bonus is added to all employees: ', Drag and drop the appropriate statement to complete the above code that adds bonus to list of salaries of employees and the output is as The bonus is added to all employees: [1390, 915, 395, 740] return salaries bonus() return num salaries = [1340, 865, 345, 690] bonus(bon) num[i] += bon main() bon bonus(salaries, bon) num[i] *= bon salaries (1340, 865, 345, 690)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Consider the following code. num = NOT_Assigned alist = [2, 0, 1, 5, 3, 4] val = 0 for i in range(0, num):     val = alist[alist[val]] print(val) What should be the smallest value assigned to num such that the number 3 is printed from the last statement print(val)? Question 9 options: 5 1 3 Not possible 0 2
The function below does not work as expected: If sales is a negative number is returns 3 instead of returning 0. Please help me correct it. /*This function determines the commision percent based on the following table:Sales Commission$0 - 1000 3%1001 - 5000 4.5%5001 - 10,000 5.25%over 10,000 6%*/double Sales::detCommissionPercent() const{double commission = 0;if ( amountSold > 0){if(amountSold<= 1000) // if amountSold is between [0, 1000]    commission = 3;else if(amountSold<=5000)// if amountSold is between [1001, 5000]    commission = 4.5;else if(amountSold<=10000) // if amountSold is between [5001, 10000]    commission = 5.25;else    commission = 6;}return commission;}
//below is the code I need help with answering the questions in the image// #include <stdio.h> #include <stdlib.h> struct employees {     char name[20];     int ssn[9];     int yearBorn, salary; }; // function to read the employee data from the user void readEmployee(struct employees *emp) {     printf("Enter name: ");     gets(emp->name);     printf("Enter ssn: ");     for (int i = 0; i < 9; i++)         scanf("%d", &emp->ssn[i]);     printf("Enter birth year: ");     scanf("%d", &emp->yearBorn);     printf("Enter salary: ");     scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() {     // creating the pointer     struct employees *emp = malloc(sizeof(struct employees));     // function to read the data     readEmployee(emp);     // returning the data     return emp; } // function to print the employee data to console void display(struct employees *e) {     printf("%s",…
Missing line of code
$majors['CS'] = 'Computer Science'; //Line 1 Smajors['MTH'] = 'Mathematics'; //Line 2 echo "The two majors are $majors['CS'] and $majors['MTH']"; //Line 3 ?> A mistake is found in (Put the line # of the statement as your answer) The corrected statement is
Last Name Dev Hours Review Date Rating Salary Bonus Brody 6 1/5/2018 2 $ 19,840 Alex 8 4/1/2018 5 $ 26,700 Ashley 1 7/1/2018 4 $ 33,200 1. Use the logical if function to pay a bonus. You determine the rules for the bonus. List the rules and your steps. For example, you may use the employee rating to align with a specific bonus percentage such as 2% for a 2 rating, 5% for a 5 rating, etc.
//below is the code I need help with answering the questions in the image// #include <stdio.h> #include <stdlib.h> struct employees { char name[20]; int ssn[9]; int yearBorn, salary; }; // function to read the employee data from the user void readEmployee(struct employees *emp) { printf("Enter name: "); gets(emp->name); printf("Enter ssn: "); for (int i = 0; i < 9; i++) scanf("%d", &emp->ssn[i]); printf("Enter birth year: "); scanf("%d", &emp->yearBorn); printf("Enter salary: "); scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() { // creating the pointer struct employees *emp = malloc(sizeof(struct employees)); // function to read the data readEmployee(emp); // returning the data return emp; } // function to print the employee data to console void display(struct employees *e) { printf("%s",…
//below is the code I need help with answering the questions in the image// #include <stdio.h> #include <stdlib.h> struct employees { char name[20]; int ssn[9]; int yearBorn, salary; }; // function to read the employee data from the user void readEmployee(struct employees *emp) { printf("Enter name: "); gets(emp->name); printf("Enter ssn: "); for (int i = 0; i < 9; i++) scanf("%d", &emp->ssn[i]); printf("Enter birth year: "); scanf("%d", &emp->yearBorn); printf("Enter salary: "); scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() { // creating the pointer struct employees *emp = malloc(sizeof(struct employees)); // function to read the data readEmployee(emp); // returning the data return emp; } // function to print the employee data to console void display(struct employees *e) { printf("%s",…
LAB ASSIGNMENTS IMPORTANT: you should complete the PDP thinking process for each program. Turn in items: 1) book_list.py: you can adapt your Chapter 4 book_list.py Lab program. The program summarizes costs of a book list. It uses all of our standard mipo_ex features. In this version of the program you must use pylnputPlus functions to perform all the input validation and for the main() loop decision. Adjust your program to allow book prices to include $ and cents. Restrict individual book prices to $100 maxium. • Clearly document, with comments, your use of the pyip functions. This program summarizes a book liat. Enter the number of books that you need: Please enter a whole number: three Enter a number greater than 0: 3 Enter the name of book #1: The Mueller Report Enter cost of The Mueller Report, to the nearest dollar: Please enter a whole number: 18 Enter the name of book #2: Educated: A Memoir Enter cost of Educated: A Memoir, to the nearest dollar: Please enter a whole number: 24…
Module/Week 2 ASSIGNMENT (INPUT/OUTPUT)The number of permutations of a set of n items taken r at a time is given by the following formulan !⁄r !(n-r)!: where n! is the factorial of n, r! is the factorial of r, and (n-r)! is the factorial of the result of n-r. The factorial of a number n can be solved using the following formula: 〖n!=e〗^(-n) n^n√2πn. If there are 18 people in your class and you want to divide the class into programming teams of 3 members, you can compute the number of different teams that can be arranged using this formula (n !⁄r !(n-r)!). Write a C++ program that determines the number of potential team arrangements. You will need to use the double type for this computation. Use the Lab Template you set-up last week, proper formatting, and appropriate comments in your code. The output must be labeled clearly and formatted neatly. Submit C++ Programming Assignment 2 by 11:59 p.m. (ET) on Monday of Module/Week 2.
Python program - It must show the correct final grade debug the code: subjects = ["Math", "English", "Science", "TLE", "Economics", "Filipino", "Laws", "History"]avg_scores = [] # stores the average scores of each subjectssum_of_avg_scores = 0 # sum of the average scores of each subjecttotal = 100 * len(subjects) # total scorefor i in range(0, len(subjects)):sum_scores = 0print("Enter the 4 exam scores of " + subjects[i] + ".(Total point per exam is 100)")for j in range(4):score = int(input())if 0 <= score <= 100:sum_scores += scoreelse:print("Enter a valid number. ")exit(0)avg_scores.append(sum_scores / 4)sum_of_avg_scores += avg_scores[i]print("The average score of " + subjects[i] + " is: " + str(avg_scores[i]))avg_scores = sum_of_avg_scores / len(subjects) # average scores of each subjectfinal_grade = avg_scores / total * 62.5 * 37 # grade formulaif 98 <= final_grade <= 100:print("The final grade is 1.00 .")elif 94 <= final_grade <= 97:print("The final grade is…
2. Identify invalid variables names from the following lists. Justify your answer. i) Student nameii) AVERAGEiii) doubleiv) _numberv) 2numbervi) number2vii) 3456viii) totalVALUEix) side_lengthx) currency$