A unique bid auction accepts an unlimited number of bids from many customers (each of whom pay a small amount to place each bid), and the winning bid is the lowest bid which is submitted by just one person (i.e. the lowest unique bid). Define a function called winning_bid (bids_list) which takes as input the list of all bids that have been made in the auction. The value returned by your function should be the lowest unique bid. If there is no lowest unique bid (in other words, if all bids appear more than once) then the function should return -1. For example, given the following bids: [3, 7, 5, 6, 3, 4, 8, 4, 5, 8, 12, 11] the winning bid is 6 as it is the lowest unique bid (because 3, 4 and 5 all appear more than once in the list of bids). For example: Test Result print(winning bid([1, 2, 3, 4, 5])) 1 print(winning bid([1, 2, 1, 4, 5])) 2 print(winning bid([1, 2, 1, 2, 5])) 5 print(winning bid([1, 1, 1, 4, 1])) 4
A unique bid auction accepts an unlimited number of bids from many customers (each of whom pay a small amount to place each bid), and the winning bid is the lowest bid which is submitted by just one person (i.e. the lowest unique bid). Define a function called winning_bid (bids_list) which takes as input the list of all bids that have been made in the auction. The value returned by your function should be the lowest unique bid. If there is no lowest unique bid (in other words, if all bids appear more than once) then the function should return -1. For example, given the following bids: [3, 7, 5, 6, 3, 4, 8, 4, 5, 8, 12, 11] the winning bid is 6 as it is the lowest unique bid (because 3, 4 and 5 all appear more than once in the list of bids). For example: Test Result print(winning bid([1, 2, 3, 4, 5])) 1 print(winning bid([1, 2, 1, 4, 5])) 2 print(winning bid([1, 2, 1, 2, 5])) 5 print(winning bid([1, 1, 1, 4, 1])) 4
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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