Answered: Deduce a Java program for the concept…

Deduce a Java program for the concept of Mutual Exclusion by using the following options. ▪ Synchronized method. ▪ Synchronized block. ▪ Static Synchronization

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Assign is Teenager with true if kidAge is 13 to 19 inclusive. Otherwise, assign is Teenager with false. 439894.2564214.qx3zqy7 1 import java.util.Scanner; □NM nor 2 3 public class TeenagerDetector { 4 5 6 7 8 9 10 11 12 13 14 15 16 17 public static void main (String [] args) { Scanner scnr = new Scanner(System.in); boolean isTeenager; int kidAge; kidAge scnr.nextInt(); * Your solution goes here if (isTeenager) { System.out.println("Teen"); } else { System.out.println("Not teen");
import java.util.Scanner; public class AverageWithSentinel{ public static final int END_OF_INPUT = -500; public static void main(String[] args) { Scanner in = new Scanner(System.in); // Step 2: Declare an int variable with an initial value // as the count of input integers // Step 3: Declare a double variable with an initial value // as the total of all input integers // Step 4: Display an input prompt // "Enter an integer, -500 to stop: " // Step 5: Read an integer and store it in an int variable // Step 6: Use a while loop to update count and total as long as // the input value is not -500. // Then display the same prompt and read the next integer // Step 7: If count is zero // Display the following message // "No integers were…
Java Program ASAP Modify this program so it passes the test cases in Hypergrade becauses it says 5 out of 7 passed. Also I need one one program and please correct and change the program so that the numbers are in the correct places as shown in the correct test case. import java.io.BufferedReader;import java.io.FileReader;import java.io.IOException;import java.util.ArrayList;import java.util.Arrays;import java.util.InputMismatchException;import java.util.Scanner;public class FileSorting { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); while (true) { System.out.println("Please enter the file name or type QUIT to exit:"); String fileName = scanner.nextLine(); if (fileName.equalsIgnoreCase("QUIT")) { break; } try { ArrayList<String> lines = readFile(fileName); if (lines.isEmpty()) { System.out.println("File " +…
import java.util.Scanner; public class LabProgram { public static Roster getInput(){ /* Reads course title, creates a roster object with the input title. Note that */ /* the course title might have spaces as in "COP 3804" (i.e. use nextLine) */ /* reads input student information one by one, creates a student object */ /* with each input student and adds the student object to the roster object */ /* the input is formatted as in the sample input and is terminated with a "q" */ /* returns the created roster */ /* Type your code here */ } public static void main(String[] args) { Roster course = getInput(); course.display(); course.dislayScores(); }} public class Student { String id; int score; public Student(String id, int score) { /* Student Employee */ /* Type your code here */ } public String getID() { /* returns student's id */…
C++. I have to make a constructor for a product. please please help me understand this, I will really appreciate this so much! I have to use this code to help make it i believe:
Given string inputStr on one line and integers idx1 and idx2 on a second line, output "Match found" if the character at index idx1 of inputStr is equal to the character at index idx2. Otherwise, output "Match not found". End with a newline. Ex: If the input is: eerie 4 1 then the output is: Match found Note: Assume the length of string inputStr is greater than or equal to both idx1 and idx2.
Java Program ASAP Modify this program so it passes the test cases in Hypergrade becauses it says 5 out of 7 passed. Also change the program so that for test cases 2 and 3 the numbers are in there correct places as shown in the input files import java.io.*;import java.util.Scanner;public class FileSorting { public static void main(String[] args) throws Exception { Scanner sc = new Scanner(System.in); System.out.println("Please enter the file name or type QUIT to exit:"); while (true) { String input = sc.next(); if (input.equalsIgnoreCase("QUIT")) { break; // Exit the program } else { String filePath = new File("").getAbsolutePath() + "/" + input; File file = new File(filePath); if (file.exists() && !file.isDirectory()) { try (BufferedReader br = new BufferedReader(new FileReader(file))) { String st;…
import java.util.Scanner; public class CircleAndSphereWhileLoop{ public static final double MAX_RADIUS = 500.0; public static void main(String[] args) { Scanner in = new Scanner(System.in); // Step 2: Read a double value as radius using prompt // "Enter the radius (between 0.0 and 500.0, exclusive): " // Step 3: While the input radius is not in the ragne (0.0, 500.0) // Display a message on one line (ssuming input value -1) // "The input number -1.00 is out of range." // Read a double value as radius using the same promt double circumference = 2 * Math.PI * radius; double area = Math.PI * radius * radius; double surfaceArea = 4 * Math.PI * Math.pow(radius, 2); double volume = (4 / 3.0) * Math.PI * Math.pow(radius, 3); // Step 4: Display the radius, circle circumference, circle area, // sphere surface area, and…
import java.util.Scanner;import java.util.InputMismatchException; public class LabProgram { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); /* Type your code here. */ }}
Using Java.
Java - How to make this a horizontal statement with a newline. Whenever I use System.out.println, it makes the output vertical instead of horizontal. What am I doing wrong? Program below. import java.util.Scanner; public class LabProgram { public static void main(String[] args) { int i; String InputString; Scanner sc = new Scanner(System.in); InputString = sc.nextLine(); char[] strArray = new char[InputString.length()]; for(i = 0; i < InputString.length(); i++){ strArray[i] = InputString.charAt(i); } for(i = 0 ; i< InputString.length() ; i++) if(strArray[i] >= 'a' && strArray[i] <= 'z' || strArray[i] >= 'A' && strArray[i] <= 'Z') System.out.print(strArray[i]); (the problem line) }}
StringFun.java import java.util.Scanner; // Needed for the Scanner class 2 3 /** Add a class comment and @tags 4 5 */ 6 7 public class StringFun { /** * @param args not used 8 9 10 11 12 public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.print("Please enter your first name: "); 13 14 15 16 17 18 System.out.print("Please enter your last name: "); 19 20 21 //Output the welcome message with name 22 23 24 //Output the length of the name 25 26 27 //Output the username 28 29 30 //Output the initials 31 32 33 //Find and output the first name with switched characters 34 //All Done! } } 35 36 37