Why does this not work The image displays an error message output commonly seen in programming environments. Below is a transcription of the text that would be typical for an educational setting:---**Java Compiler Error Example: Understanding "Cannot Find Symbol"**In this example, we observe a common compilation error that occurs when the Java compiler cannot find a referenced variable or method. This typically happens when the variable is either not declared or out of scope. Here is a breakdown of the error output:```MyProgram.java:20: error: cannot find symbolif (rsvp = true && number == 1) { ^ symbol: variable number location: class MyProgramMyProgram.java:23: error: cannot find symbolelse if (rsvp = true && number == 2) { ^ symbol: variable number location: class MyProgramMyProgram.java:26: error: cannot find symbolelse if (rsvp = true && number == 3) { ^ symbol: variable number location: class MyProgram```**Key Points:**1. **Error Type**: `cannot find symbol` - This indicates that the compiler cannot resolve a reference to a variable or method. 2. **Mistake in the Code**: - The variable `number` is not recognized in the context it's being used. This could be due to it not being declared before use or not being in the scope of the method or class.3. **Lines with Errors**: - The errors occur on lines 20, 23, and 26, where the code attempts to evaluate a condition involving `number`.4. **Probable Causes**: - The variable `number` might not have been declared in the class `MyProgram`. - It might be a case of a typo or incorrect variable name.**Resolution Tips**:- Check if the variable `number` has been declared appropriately within the class or method.- Ensure correct spelling and capitalization as Java is case-sensitive.- Consider the scope of variable `number`; it should be accessible within the class `MyProgram`.Understanding and fixing such compilation errors is essential for efficient Java programming and debugging.--- This transcription and explanation provide a foundational understanding of the "cannot find symbol" error, helping learners effectively troubleshoot and resolve similar issues in their code. ```javaimport java.util.Scanner;public class MyProgram{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.println("Answer true or false, Are you attending? "); boolean rsvp = sc.nextBoolean(); if(!rsvp) { System.out.println("Sorry you can't make it"); } if(rsvp == true){ System.out.println("Please enter a menu number: "); int number = sc.nextInt(); if(rsvp == true && number == 1) { System.out.println("Thanks for attending. You will be served beef."); } else if(rsvp == true && number == 2) { System.out.println("Thanks for attending. You will be served chicken."); } else if(rsvp == true && number == 3) { System.out.println("Thanks for attending. You will be served pasta."); } else { System.out.println("Thank you for attending. You will be served fish."); } } }}```### DescriptionThis Java program, named `MyProgram`, is designed to handle the attendance status and menu preference of a guest. It utilizes the `Scanner` class to accept user input. Here is an explanation of how the program operates:1. The program begins by outputting a prompt asking whether the user is attending: "Answer true or false, Are you attending?" This expects a boolean (true/false) input.2. If the response (`rsvp`) is `false`, the program will respond with "Sorry you can't make it" and terminate further operations.3. If `rsvp` is `true`, the user is prompted to enter a menu number: "Please enter a menu number:".4. Depending on the number entered (1, 2, or 3), a corresponding message is printed: - Number 1: "Thanks for attending. You will be served beef." - Number 2: "Thanks for attending. You will be served chicken." - Number 3: "Thanks for attending. You will be served pasta." 5. If a different number is entered, the program defaults to: "Thank you for attending. You will be served fish."This simple program encodes conditional logic to manage event attendance and meal selection based on user input.

Import the Scanner class from the java.util package.Declare a class named Main.Inside the…

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Why does this not work

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

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Concept explainers

Fundamentals of Input and Output Performance

The I/O subsystem is a component of computer system design that uses buses to assist communication between the Central Processing Unit, Computer Memory/Storage, and Input and Output Devices (that is known as peripheral devices). The I/O subsystem includes disc controllers, tape drives, discs, system buses, and other devices. The I/O database application reads and writes drives using the operating system windows I/O.

Question

Why does this not work

The image displays an error message output commonly seen in programming environments. Below is a transcription of the text that would be typical for an educational setting:

---

**Java Compiler Error Example: Understanding "Cannot Find Symbol"**

In this example, we observe a common compilation error that occurs when the Java compiler cannot find a referenced variable or method. This typically happens when the variable is either not declared or out of scope. Here is a breakdown of the error output:

```
MyProgram.java:20: error: cannot find symbol
if (rsvp = true && number == 1) {
^
symbol: variable number
location: class MyProgram

MyProgram.java:23: error: cannot find symbol
else if (rsvp = true && number == 2) {
^
symbol: variable number
location: class MyProgram

MyProgram.java:26: error: cannot find symbol
else if (rsvp = true && number == 3) {
^
symbol: variable number
location: class MyProgram
```

**Key Points:**

1. **Error Type**: `cannot find symbol`
- This indicates that the compiler cannot resolve a reference to a variable or method.

2. **Mistake in the Code**:
- The variable `number` is not recognized in the context it's being used. This could be due to it not being declared before use or not being in the scope of the method or class.

3. **Lines with Errors**:
- The errors occur on lines 20, 23, and 26, where the code attempts to evaluate a condition involving `number`.

4. **Probable Causes**:
- The variable `number` might not have been declared in the class `MyProgram`.
- It might be a case of a typo or incorrect variable name.

**Resolution Tips**:
- Check if the variable `number` has been declared appropriately within the class or method.
- Ensure correct spelling and capitalization as Java is case-sensitive.
- Consider the scope of variable `number`; it should be accessible within the class `MyProgram`.

Understanding and fixing such compilation errors is essential for efficient Java programming and debugging.

---

This transcription and explanation provide a foundational understanding of the "cannot find symbol" error, helping learners effectively troubleshoot and resolve similar issues in their code.

```java
import java.util.Scanner;
public class MyProgram
{
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);

System.out.println("Answer true or false, Are you attending? ");
boolean rsvp = sc.nextBoolean();
if(!rsvp) {
System.out.println("Sorry you can't make it");
}

if(rsvp == true){
System.out.println("Please enter a menu number: ");
int number = sc.nextInt();

if(rsvp == true && number == 1) {
System.out.println("Thanks for attending. You will be served beef.");
}
else if(rsvp == true && number == 2) {
System.out.println("Thanks for attending. You will be served chicken.");
}
else if(rsvp == true && number == 3) {
System.out.println("Thanks for attending. You will be served pasta.");
}
else {
System.out.println("Thank you for attending. You will be served fish.");
}
}
}
}
```

### Description

This Java program, named `MyProgram`, is designed to handle the attendance status and menu preference of a guest. It utilizes the `Scanner` class to accept user input. Here is an explanation of how the program operates:

1. The program begins by outputting a prompt asking whether the user is attending: "Answer true or false, Are you attending?" This expects a boolean (true/false) input.

2. If the response (`rsvp`) is `false`, the program will respond with "Sorry you can't make it" and terminate further operations.

3. If `rsvp` is `true`, the user is prompted to enter a menu number: "Please enter a menu number:".

4. Depending on the number entered (1, 2, or 3), a corresponding message is printed:
- Number 1: "Thanks for attending. You will be served beef."
- Number 2: "Thanks for attending. You will be served chicken."
- Number 3: "Thanks for attending. You will be served pasta."

5. If a different number is entered, the program defaults to: "Thank you for attending. You will be served fish."

This simple program encodes conditional logic to manage event attendance and meal selection based on user input.

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