Decode the message ACXUT CXRT, which was encrypted using the congruence c ≡ (3p + 5) mod 26 that corresponds to the previous table (cyclical English alphabet. Write the plaintext on the space provided below. 24121426the corresponding letter in the ciphertext message is given by;ugC IIIIII positions, thenc = (p + m)mod 26where c is the encrypted code, p is the number corresponds to a letter in an English alphabetin a normal position, m is the shifted position and n = 26 is the modulus since there are 26letters in an English alphabet.TableCyclical English AlphabetabdeFikmqp.16uV13.810111213 1415171819 202122 23 24 25 0-9-8-7-6-5-4-3-2-1252322 212019181716151413 121110Note that the letter Z is coded as zero because 26 = 0 mod 26.185

Given c≡3p+5mod 26 Give cipher text is ACXUT CXRT To find the plain text: First solve the given…

Answered: Decode the message ACXUT CXRT, which…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

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Decode the message ACXUT CXRT, which was encrypted using the congruence c ≡ (3p + 5) mod 26 that corresponds to the previous table (cyclical English alphabet. Write the plaintext on the space provided below.

24
12
14
26
the corresponding letter in the ciphertext message is given by;
ugC III
III positions, then
c = (p + m)mod 26
where c is the encrypted code, p is the number corresponds to a letter in an English alphabet
in a normal position, m is the shifted position and n = 26 is the modulus since there are 26
letters in an English alphabet.
Table
Cyclical English Alphabet
a
b
d
e
F
i
k
m
q
p.
16
u
V
1
3.
8
10
11
12
13 14
15
17
18
19 20
21
22 23 24 25 0
-9
-8
-7
-6
-5
-4
-3
-2
-1
25
23
22 21
20
19
18
17
16
15
14
13 12
11
10
Note that the letter Z is coded as zero because 26 = 0 mod 26.
185

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