Decode the message ACXUT CXRT, which was encrypted using the congruence c ≡ (3p + 5) mod 26 that corresponds to the previous table (cyclical English alphabet. Write the plaintext on the space provided below. 24121426the corresponding letter in the ciphertext message is given by;ugC IIIIII positions, thenc = (p + m)mod 26where c is the encrypted code, p is the number corresponds to a letter in an English alphabetin a normal position, m is the shifted position and n = 26 is the modulus since there are 26letters in an English alphabet.TableCyclical English AlphabetabdeFikmqp.16uV13.810111213 1415171819 202122 23 24 25 0-9-8-7-6-5-4-3-2-1252322 212019181716151413 121110Note that the letter Z is coded as zero because 26 = 0 mod 26.185

Given c≡3p+5mod 26 Give cipher text is ACXUT CXRT To find the plain text: First solve the given…

Decode the message ACXUT CXRT, which was encrypted using the congruence c ≡ (3p + 5) mod 26 that corresponds to the previous table (cyclical English alphabet. Write the plaintext on the space provided below.

Decode the message ACXUT CXRT, which was encrypted using the congruence c ≡ (3p + 5) mod 26 that corresponds to the previous table (cyclical English alphabet. Write the plaintext on the space provided below.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

24
12
14
26
the corresponding letter in the ciphertext message is given by;
ugC III
III positions, then
c = (p + m)mod 26
where c is the encrypted code, p is the number corresponds to a letter in an English alphabet
in a normal position, m is the shifted position and n = 26 is the modulus since there are 26
letters in an English alphabet.
Table
Cyclical English Alphabet
a
b
d
e
F
i
k
m
q
p.
16
u
V
1
3.
8
10
11
12
13 14
15
17
18
19 20
21
22 23 24 25 0
-9
-8
-7
-6
-5
-4
-3
-2
-1
25
23
22 21
20
19
18
17
16
15
14
13 12
11
10
Note that the letter Z is coded as zero because 26 = 0 mod 26.
185

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