An amateur cryptographer wants to encrypt the message "abcde" using two different affine ciphers. The first affine cipher uses the affine function 177x102 (mod 26) on the message "abcde" yielding a five letter encrypted message M₁. The second affine cipher uses the affine function 137154 (mod 26) on the message M₁ yielding a five letter encrypted message M₂. Find constants A, B,0 ≤ A, B ≤ 25, such that the affine function Ax+B (mod 26) will directly encrypted the original message "abcde" as M₂ without the intermediate step. Compute VA+ B. Round to two decimal places.
An amateur cryptographer wants to encrypt the message "abcde" using two different affine ciphers. The first affine cipher uses the affine function 177x102 (mod 26) on the message "abcde" yielding a five letter encrypted message M₁. The second affine cipher uses the affine function 137154 (mod 26) on the message M₁ yielding a five letter encrypted message M₂. Find constants A, B,0 ≤ A, B ≤ 25, such that the affine function Ax+B (mod 26) will directly encrypted the original message "abcde" as M₂ without the intermediate step. Compute VA+ B. Round to two decimal places.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Difficult Intro to Elementary Number Theory Homework problem. This is not a computer programming homework problem.

Transcribed Image Text:An amateur cryptographer wants to encrypt the message "abcde" using two different affine ciphers. The first affine cipher uses the affine function
177x + 102 (mod 26)
on the message "abcde" yielding a five letter encrypted message M₁. The second affine cipher uses the affine function
137x + 154 (mod 26)
on the message M₁ yielding a five letter encrypted message M₂.
Find constants A, B,0 ≤ A, B ≤ 25, such that the affine function
Ax+B (mod 26)
will directly encrypted the original message "abcde" as M₂ without the intermediate step. Compute √A+ B. Round to two decimal places.
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