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Solve a subtraction problem (2-digit or 3-digit with regrouping, example: 222-56, using two of these methods a. Describe why the method works and give a mathematical explanation. (Because the next step is… OR Because it gets you the right answer…is not a mathematical explanation). What makes the method a viable method

Solve a subtraction problem (2-digit or 3-digit with regrouping, example: 222-56, using two of these methods a. Describe why the method works and give a mathematical explanation. (Because the next step is… OR Because it gets you the right answer…is not a mathematical explanation). What makes the method a viable method

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Solve a subtraction problem (2-digit or 3-digit with regrouping, example: 222-56, using two of these methods a. Describe why the method works and give a mathematical explanation. (Because the next step is… OR Because it gets you the right answer…is not a mathematical explanation). What makes the method a viable method that works with any problem?
Method E 32,427 -15,826 Method F 53 53 -38 +61 X14 351 - 85 + 15 351 +914 X265 1 266 + Start on the left. 3 - 1 is 2, but before I write that down, I look at the next column to see if there's going to be a problem. There is, so make the 2 a 1 and write it down. I can't take 5 from 2, so I do a different procedure: figure out how many more it will take to make the 5 a ten (it's 5), then add that to the 2 to get 7. But before I write that down, I check the next column over. There's a problem, so reduce the 7 by 1 to get 6 and write it down. For 4-8, I need to do my alternative procedure: It'll take 2 more to make 10, then add that to 4 to get 6. But check the next column before going on. I can't tell with 2-2, so check the next column. 7 - 6 won't be a problem, so write down the original 6 under 4 - 8. 2 - 2 is 0, and there is no problem in the next column so write it down. 7-6 is 1, and there is no next column, so write it down. The answer is 16,601. Transform into an addition problem by subtracting each number in the bottom (subtrahend) from 9. Thus, 3 becomes 6, 8 becomes 1. Now add. When done, drop the 1 in the largest place and add 1 to the ones place to get the answer of 15. Basically the same, but be sure to replace leading (invisible) zeros with 9.
Transcribed Image Text:Method E 32,427 -15,826 Method F 53 53 -38 +61 X14 351 - 85 + 15 351 +914 X265 1 266 + Start on the left. 3 - 1 is 2, but before I write that down, I look at the next column to see if there's going to be a problem. There is, so make the 2 a 1 and write it down. I can't take 5 from 2, so I do a different procedure: figure out how many more it will take to make the 5 a ten (it's 5), then add that to the 2 to get 7. But before I write that down, I check the next column over. There's a problem, so reduce the 7 by 1 to get 6 and write it down. For 4-8, I need to do my alternative procedure: It'll take 2 more to make 10, then add that to 4 to get 6. But check the next column before going on. I can't tell with 2-2, so check the next column. 7 - 6 won't be a problem, so write down the original 6 under 4 - 8. 2 - 2 is 0, and there is no problem in the next column so write it down. 7-6 is 1, and there is no next column, so write it down. The answer is 16,601. Transform into an addition problem by subtracting each number in the bottom (subtrahend) from 9. Thus, 3 becomes 6, 8 becomes 1. Now add. When done, drop the 1 in the largest place and add 1 to the ones place to get the answer of 15. Basically the same, but be sure to replace leading (invisible) zeros with 9.
Method C 53 -385 20 401 - 287 200 - 80 120 6 114 80 -6 3 minus 8 is negative 5. I'm going to hold that in my head while I do the tens. 50 minus 30 is 20. Combine negative 5 and the 20 and my answer is 15. If I wanted to, I could have written down the 20 and -5 below that and gotten 15. 400 minus 200 is 200. Nothing minus 80 is -80. 1 minus 7 is negative 6. I take the 80 from the 200 and get 120. Then I take away 6 more and get 114. Method D 53 55 -38-40 15 401 ૧૦૧ -287 -290 -300 414 114 53 - 38 is too hard, so add 2 to the 53 and 2 to the 38 making 55-40. The answer is 15. 401 - 287 is too hard. Make it 404 - 290, but you're still not done. That becomes 414-300, which is easy, so subtract!
Transcribed Image Text:Method C 53 -385 20 401 - 287 200 - 80 120 6 114 80 -6 3 minus 8 is negative 5. I'm going to hold that in my head while I do the tens. 50 minus 30 is 20. Combine negative 5 and the 20 and my answer is 15. If I wanted to, I could have written down the 20 and -5 below that and gotten 15. 400 minus 200 is 200. Nothing minus 80 is -80. 1 minus 7 is negative 6. I take the 80 from the 200 and get 120. Then I take away 6 more and get 114. Method D 53 55 -38-40 15 401 ૧૦૧ -287 -290 -300 414 114 53 - 38 is too hard, so add 2 to the 53 and 2 to the 38 making 55-40. The answer is 15. 401 - 287 is too hard. Make it 404 - 290, but you're still not done. That becomes 414-300, which is easy, so subtract!
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