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Solve a subtraction problem (2-digit or 3-digit with regrouping, example: 213 - 59). a. Describe why the method works and give a mathematical explanation. What makes the method a viable method that works with any problem?

Solve a subtraction problem (2-digit or 3-digit with regrouping, example: 213 - 59). a. Describe why the method works and give a mathematical explanation. What makes the method a viable method that works with any problem?

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Solve a subtraction problem (2-digit or 3-digit with regrouping, example: 213 - 59). a. Describe why the method works and give a mathematical explanation. What makes the method a viable method that works with any problem?
Method C 53 -385 20 401 - 287 200 - 80 120 6 114 80 -6 3 minus 8 is negative 5. I'm going to hold that in my head while I do the tens. 50 minus 30 is 20. Combine negative 5 and the 20 and my answer is 15. If I wanted to, I could have written down the 20 and -5 below that and gotten 15. 400 minus 200 is 200. Nothing minus 80 is -80. 1 minus 7 is negative 6. I take the 80 from the 200 and get 120. Then I take away 6 more and get 114. Method D 53 55 -38-40 15 401 ૧૦૧ -287 -290 -300 414 114 53 - 38 is too hard, so add 2 to the 53 and 2 to the 38 making 55-40. The answer is 15. 401 - 287 is too hard. Make it 404 - 290, but you're still not done. That becomes 414-300, which is easy, so subtract!
Transcribed Image Text:Method C 53 -385 20 401 - 287 200 - 80 120 6 114 80 -6 3 minus 8 is negative 5. I'm going to hold that in my head while I do the tens. 50 minus 30 is 20. Combine negative 5 and the 20 and my answer is 15. If I wanted to, I could have written down the 20 and -5 below that and gotten 15. 400 minus 200 is 200. Nothing minus 80 is -80. 1 minus 7 is negative 6. I take the 80 from the 200 and get 120. Then I take away 6 more and get 114. Method D 53 55 -38-40 15 401 ૧૦૧ -287 -290 -300 414 114 53 - 38 is too hard, so add 2 to the 53 and 2 to the 38 making 55-40. The answer is 15. 401 - 287 is too hard. Make it 404 - 290, but you're still not done. That becomes 414-300, which is easy, so subtract!
Method B 5'3 338 15 60'3 $895 208 You can't take 8 from 3, so you make the three 13. That means you have to make the 3 tens you're taking away into 4 tens. Then you subtract: 8 from 13 is 5,4 from 5 is 1. This is basically the same method as before, but you apply it repeatedly. The 9 tens become 10 tens, but those can be taken from 10 tens above.
Transcribed Image Text:Method B 5'3 338 15 60'3 $895 208 You can't take 8 from 3, so you make the three 13. That means you have to make the 3 tens you're taking away into 4 tens. Then you subtract: 8 from 13 is 5,4 from 5 is 1. This is basically the same method as before, but you apply it repeatedly. The 9 tens become 10 tens, but those can be taken from 10 tens above.
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