ructure-molecular structuretod.methanesilicasulphuroxygengraphiteethanolsodium chlorideteiodinenaphthalenediamondwaterhacopper(I) sulphatepotassium hydroxidehydrogen chloridesulphur dioxideThis table gives information about some propertiesiceammoniacanitrogenphosphorusbrominearsteameleof certain substances A to G.poBroSubstanceM.pt.°CElectricalPerSolubilityin waterconductivityasolidliquid-112 poor680 poor-70 poor1495 good610 poor1610 poor660 goodрorgoodpoorgoodgoodpoorgoodinsolublesolubleinsolubleinsolublesolubleinsolubleinsolubled.G.4 a LaWhich of the substances are metals? Givereasons for your choice.b Which of the substances are ionic compounds?Give reasons for your choice.Two of the substances have very low meltingpoints, compared with the rest. Explain why thesecould not be ionic compounds.d Two of the substances are molecular. Which!!b Giic Etaftdoones are they?Which substance is a giant covalent structure?

There are different types of substances that act differently in the presence of electricity. There…

de 1 This table gives information about some properties of certain substances A to G. Substance М.pt. °C Electrical conductivity liquid Solubility in water solid -112 poor 680 poor -70 poor 1495 good 610 | роor 1610 insoluble soluble poor good poor good good рoor good B. insoluble insoluble D. soluble insoluble poor 660 good insoluble a Which of the substances are metals? Give reasons for your choice. b Which of the substances are ionic compounds? Give reasons for your choice. Two of the substances have very low melting points, compared with the rest. Explain why these could not be ionic compounds.

de 1 This table gives information about some properties of certain substances A to G. Substance М.pt. °C Electrical conductivity liquid Solubility in water solid -112 poor 680 poor -70 poor 1495 good 610 | роor 1610 insoluble soluble poor good poor good good рoor good B. insoluble insoluble D. soluble insoluble poor 660 good insoluble a Which of the substances are metals? Give reasons for your choice. b Which of the substances are ionic compounds? Give reasons for your choice. Two of the substances have very low melting points, compared with the rest. Explain why these could not be ionic compounds.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

From the standardization data, calculate the molarity of the sodium hydroxide solution for each trial. Average the values and enter the average in the Standardization Data Table.
There are two instances where waste streams from reactions would need to be processedcan you identify them?
[Nonacid] Molecules Dissolve... Intact hmg H2O C12H22011(s) → C,2H22O11(aq) A2??4 Covalent chemical bonds! H2O CH5OH(s)→ Co Hs OH (aq) H2O (sand) SiO,(s)→ → Molecular nonacid solutes disperse to single molecules (_) ...but no further! Dissolved nonacid molecules stay whole
0.529 47.629 1. Initial mass of copper 2. Mass of copper and evaporating dish 3. Mass of evaporating dish 4. Mass of recovered copper 5. Percent yield (show cafcuntions) 6. Describe the reaction Cu(s)+HNO3(aq)→. 7. Describe the reaction Cu(NO3)2(aq)+NaOH(aq)→. 8. Describe the reaction Cu(OH)2(s)-A. 9. What are you removing by this washing? 10. What copper compound is present in the beaker? 11. Describe the reaction CuSO4(aq)+Zn(s) or CuSO4(aq)+ AI(s). 12. What is present in solution? 13. What is the gas? 14. How do you know? 15. What are you removing by washing? 16. What color is your copper sample? 17. Is it uniform in appearance? 18. Suggest possible sources of error in this experiment.
y D a -h 14. The unknown tablet is prepared for analysis in two steps. The tablet is crushed into a powder and then dissolved into a 250 mL volumetric flask with dilute acetic acid. A diluted powder solution is prepared by transferring 25.00 mL of the original powder solution into a 50 mL volumetric flask and diluting to volume with dilute acetic acid. Then 1.00 mL of the diluted powder solution is added to each of the standard addition flasks; each flask has a total volume of 10.00 mL. The unknown's riboflavin concentration in the standard addition solutions is determined to be 1.41 ppm. What is the riboflavin concentration (ppm) in the unknown powder solution? 2.82 21.2 14.1 28.2
1 of 4 Watch the video that shows using the dilution method to make a solution of known concentration. Note that while the video shows the use of a beaker, in the lab we typically use a volumetric flask to make the diluted solution. The stock solution of KMNO, has a concentration of 2.6 x 10ª M. The pipette has a volume of 10.0 mL. What is the amount of KMNO. delivered to the solution, in moles? mol Submit When using the dilution method to prepare a solution of known concentration, remember that the total amount of solute is the same in both the measured volume of the more concentrated stock solution and in the dilute solution created. This means we can use a simple ennation (Emation 4 2) to calculate the volume or concentration of either the stock solution or the more dilute solution Fauation 4 2 is stv hulu W
If 142.35 mL of 64.61 mM MgCl2 is mixed together with 164.59 mL of 208.37 mM AgNO3, determine the mass of the solid that forms. Report your answer in mg Round your answer to 1 decimal place
The equation for dilution of a solution is ?1?1=?2?2M1⁢V1=M2⁢V2 where ?1M1 and ?1V1 are the initial concentration and volume, respectively, and ?2M2 and ?2V2 represent the final concentration and volume, respectively. When preparing a dilute solution, it is necessary to first calculate the volume of stock solution needed. Which of the expressions is equal to the volume of stock solution, ?1?V1? ?2?2?1M2⁢V2M1 ?1?2?2M1⁢M2V2 ?2?1?1
Masses : Ca = 40.08 g S= 32.07 g O= 16.00 g A 35.0 mL sample of CaSO4 was evaporated to dryness, leaving 0.967 g of residue. What was the molarity of the original solution? step by step please