Data Processing) A clever and simple method of preparing to sort dates into ascending (increasing) or descending (decreasing) order is to convert a date in the form month/day/year into an integer number with the formula date = year × 10000 + month × 100 + day. For example, using this formula, the date 12/6/1988 converts to the integer 19881206, and the date 2/28/2010 converts to the integer 20100228. Sorting the resulting integer numbers puts dates into the correct order automatically. Using this formula, write a function named convertdays() that accepts a month, day, and year; converts the passed data into a single date integer; and returns the integer to the calling function.
Please do the C++ programme in a simple and step by step method.
Q7.
(Data Processing) A clever and simple method of preparing to sort dates into ascending (increasing) or descending (decreasing) order is to convert a date in the form month/day/year into an integer number with the formula date = year × 10000 + month × 100 + day. For example, using this formula, the date 12/6/1988 converts to the integer 19881206, and the date 2/28/2010 converts to the integer 20100228. Sorting the resulting integer numbers puts dates into the correct order automatically. Using this formula, write a function named convertdays() that accepts a month, day, and year; converts the passed data into a single date integer; and returns the integer to the calling function.
b.
Include the convertdays() function written for Exercise 7a in a working program. The main() function should call convertdays() correctly and display the integer the function returns.
thanks in advance
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