Data on the numbers of hospital admissions resulting from motor vehicle crashes are given below for Fridays on the 6th of a month and Fridays on the following 13th of the same month. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Construct a 95% confidence interval estimate of the mean of the population of differences between hospital admissions. Use the confidence interval to test the claim that when the 13th day of a month falls on a Friday, the numbers of hospital admissions from motor vehicle crashes are not affected. Friday the 6th 4 11 7 4 Friday the 13th 11 11 14 13 14 In this example, Ha is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the number of hospital admissions on Friday the 6th minus the number of hospital admissions on Friday the 13th. Find the 95% confidence interval. (Round to two decimal places as needed.) Based on the confidence interval, can one reject the claim that when the 13th day of a month falls on a Friday, the numbers of hospital admissions from motor vehicle crashes are affected? O A. No, because the confidence interval does not include zero. O B. Yes, because the confidence interval does not include zero. O c. Yes, because the confidence interval includes zero. O D. No, because the confidence interval includes zero.

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### Data Analysis of Hospital Admissions on Friday the 13th

**Objective:**
To analyze whether the 13th day of a month falling on a Friday influences the number of hospital admissions due to motor vehicle crashes.

**Data Description:**
Hospital admission data on the 6th and 13th (when it falls on a Friday) of the same month:
- **Friday the 6th Admissions:** 4, 11, 7, 5, 4
- **Friday the 13th Admissions:** 11, 14, 13, 13, 14

**Analysis Task:**
Construct a 95% confidence interval for the mean of the differences between hospital admissions on these two Fridays. This tests the hypothesis that there is no significant change in hospital admissions.

**Definitions:**
- Each difference \( d \) is defined as: \( d = \) (Admissions on Friday the 6th) - (Admissions on Friday the 13th).

**Confidence Interval Calculation:**
- Define \( \mu_d \) as the mean value of all differences.
- Create a 95% confidence interval to assess \( \mu_d \).

**Confidence Interval:**
\[ \_\ < \mu_d < \_ \]
*(Values are to be calculated and rounded to two decimal places.)*

**Conclusion Assessment:**

Using the confidence interval, address the primary question:
- Can we reject the hypothesis that Fridays on the 13th lead to increased admissions?

**Answer Options:**
- **A.** No, because the confidence interval does not include zero.
- **B.** Yes, because the confidence interval does not include zero.
- **C.** Yes, because the confidence interval includes zero.
- **D.** No, because the confidence interval includes zero.

To complete the analysis, calculate the confidence interval and select the appropriate conclusion based on the results.

**Educational Note:**
Understanding confidence intervals is critical for assessing the significance of results in hypothesis testing. This helps determine if observed effects are due to random variations or indicate a real influence of the tested variable—in this case, the date.
Transcribed Image Text:### Data Analysis of Hospital Admissions on Friday the 13th **Objective:** To analyze whether the 13th day of a month falling on a Friday influences the number of hospital admissions due to motor vehicle crashes. **Data Description:** Hospital admission data on the 6th and 13th (when it falls on a Friday) of the same month: - **Friday the 6th Admissions:** 4, 11, 7, 5, 4 - **Friday the 13th Admissions:** 11, 14, 13, 13, 14 **Analysis Task:** Construct a 95% confidence interval for the mean of the differences between hospital admissions on these two Fridays. This tests the hypothesis that there is no significant change in hospital admissions. **Definitions:** - Each difference \( d \) is defined as: \( d = \) (Admissions on Friday the 6th) - (Admissions on Friday the 13th). **Confidence Interval Calculation:** - Define \( \mu_d \) as the mean value of all differences. - Create a 95% confidence interval to assess \( \mu_d \). **Confidence Interval:** \[ \_\ < \mu_d < \_ \] *(Values are to be calculated and rounded to two decimal places.)* **Conclusion Assessment:** Using the confidence interval, address the primary question: - Can we reject the hypothesis that Fridays on the 13th lead to increased admissions? **Answer Options:** - **A.** No, because the confidence interval does not include zero. - **B.** Yes, because the confidence interval does not include zero. - **C.** Yes, because the confidence interval includes zero. - **D.** No, because the confidence interval includes zero. To complete the analysis, calculate the confidence interval and select the appropriate conclusion based on the results. **Educational Note:** Understanding confidence intervals is critical for assessing the significance of results in hypothesis testing. This helps determine if observed effects are due to random variations or indicate a real influence of the tested variable—in this case, the date.
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