Data on fifth-grade test scores (reading and mathematics) for 428 school districts in California yield Y=594.5 and standard deviation sy = 17.9The 95% confidence interval for the mean test score in the population is (592 80 596.20). (Round your responses to two decimal places)When the districts were divided into districts with small classes (<20 students per teacher) and large classes (2 20 students per teacher), the following results were foundAverage Score (Y)Standard Deviation (Sy)604 B598.0Class SizeSmallLarge17.816.5Is there statistically significant evidence that the districts with smaller classes have higher average test scores?The I-statistic for testing the null hypothesis is 4.01 (Round your response to two decimal places)The p-value for the test is (Round your response to six decimal places) Hint: Use the Excel function Norm S. Dist to help answer this question.n237177

Suppose the data on fifth-grade test scores (reading and mathematics) for the school districts in…

Answered: Data on fifth-grade test scores…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean change in muscle thickness observed after a 4-week training regimen was 4 mm, and the 95% confidence interval (CI) for mean change was (-0.5, 8.5). Which is the best scientific conclusion for the effectiveness of this regimen ?
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A sample of 106 body temperatures was taken and the mean was 98.2 degrees F. The population standard deviation is 0.62 degrees. Use a 0.05 level of significance to test the claim that the average body temperature is actually different than 98.6 degrees F. Find the 95% confidence interval of the mean temperature and compare your results.
Identify the t-score for a 95% confidence interval if the sample size is 15. t = the answer isnt 2.131 so what is the answer?
In a study of the use of hypnosis to relieve pain, sensory ratings were measured for 8 subjects and the mean sensory ratings was found to be 2.8 and standard deviation to be 0.3. The sensory ratings are normally distributed. The 80% confidence interval for the mean sensory ratings of the population is (9.35,11.65) b. (3.58, 4.64) (2.65, 2.95) d. (3.09, 3.91) (6.27, 8.73) a. C. e.
A repeated measures study is done to measure the change in IQ test scores taken on Monday versus those taken on Friday. There were n=9 participants in the study. The mean difference was MD =-5 points and the standard error for the mean difference was SMD=0.51. Construct a 95% confidence interval to estimate the size of the population mean difference.
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The mean score on the math portion of the ACT for the year 2000 is μ = 20.7. A sample of 20 students in a local school district had a mean of 22.95. Using the sample, a 95% confidence interval estimate for the mean is (20.76, 25.14). State the point estimate for the mean ACT score for students. Based on this sample information , do you believe that the local students have a mean different from the general population? Why? 22.95 is in the center of the interval. The means are definitely not different. 22.95 is just outside the 95% confidence interval. Can't say the means are really different. 22.95 is not equal to 20.7. The means are definitely different. 20.7 is just outside the 95% confidence interval. Can't say the means are really different.
Researchers examined the bill color (in hue degree) of male and female zebra finches. Here are the summary statistics from the study. Sex N Mean Standard deviation Males 59 2.91 1.46 Females 60 7.42 2.48 How different are male and female zebra finches in bill color? The margin of error for a 95% confidence interval for the difference in mean bill color μF – μM (in hue degree) is
Dr. Higney, an academic researcher in an English department, wants to learn about the average length of a novel. In order to do this, Dr. Higney collects data on the word counts of 200 randomly selected novels. The sample mean of this data set is = 85252 with a sample standard deviation of 8413 words. Using this data, construct a 90% confidence interval for the true mean length of novels. (84,273.50, 86,230.51) (82719.67,89784.33) (94086.04, 96417.96) (80937.53, 90566.47) S
A researcher collected data on a sample of 40 stores of a large retail chain, and for each store translate data to a conventional performance rating. The average performance rating among sample values is calculated to be 275. calculate an approxiate 95% confidence interval for the mean performance rating of all stories of the chain. Assume the standard deviation of performance ratings among all store in the chain is 90.

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