Data: Mass of Mg = 0.0235 g Volume of H2(g): 24.20 mL. Temperature of H2O: 20.0 °C H2O vapor pressure: 17.8 mmHg Total pressure : 758.0 mmHg Calculation: Moles of H2 (g) g of Mg. → moles of Mg- → moles of H₂: a Convert temperature of H2O to K: Pressure of H₂(g): PH2: total pressure - water vapor pressure: in mmHg : convert it to atm. 1 tm. = 760 mmHg Convert volume of H₂ to L. IL. = 1000 mL. PV = nRT R=PV/nT R = (PH2 in atm. X volume of H2 in L.)/(moles of H2 x 293.0 K): R in atm. L. / mole K Calculate the %error: ((0.0821- calculated R)/ 0.0821) x100

Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter13: Gases
Section: Chapter Questions
Problem 140AP: he following demonstration takes place in a two-step process: rst, solid calcium carbide...
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Data:
Mass of Mg = 0.0235 g
Volume of H2(g): 24.20 mL.
Temperature of H2O: 20.0 °C
H2O vapor pressure: 17.8 mmHg
Total pressure : 758.0 mmHg
Calculation:
Moles of H2 (g)
g of Mg
→ moles of Mg
moles of H₂ : a
Convert temperature of H2O to K:
: convert
Pressure of H₂(g): PH2 total pressure - water vapor pressure : in mmHg :
it to atm.
1 tm. = 760 mmHg
Convert volume of H₂ to L.
1L. = 1000 mL.
PV = nRT
R=PV/nT
R = (PH2 in atm. X volume of H2 in L. ) / (moles of H2 x 293.0 K): R in atm. L. /
mole K
Calculate the %error: ((0.0821- calculated R)/ 0.0821) x100
Transcribed Image Text:Data: Mass of Mg = 0.0235 g Volume of H2(g): 24.20 mL. Temperature of H2O: 20.0 °C H2O vapor pressure: 17.8 mmHg Total pressure : 758.0 mmHg Calculation: Moles of H2 (g) g of Mg → moles of Mg moles of H₂ : a Convert temperature of H2O to K: : convert Pressure of H₂(g): PH2 total pressure - water vapor pressure : in mmHg : it to atm. 1 tm. = 760 mmHg Convert volume of H₂ to L. 1L. = 1000 mL. PV = nRT R=PV/nT R = (PH2 in atm. X volume of H2 in L. ) / (moles of H2 x 293.0 K): R in atm. L. / mole K Calculate the %error: ((0.0821- calculated R)/ 0.0821) x100
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