Two Sample t-testdata: Dental by Gendert = 3.8623, df = 25, p-value = 0.000705alternative hypothesis: true difference in means is not equal to 095 percent confidence interval:1.576648 5.179034sample estimates:mean in group B mean in group G27.4687524.09091Welch Two Sample t-testdata: Dental by Gendert = 3.7488, df = 19.334, p-value = 0.001327alternative hypothesis: true difference in means is not equal to 095 percent confidence interval:1.494121 5.261561sample estimates:mean in group B mean in group G27.4687524.09091302826Dental24zz220BGenderG

Solution:- Given that the analysis results of two sample t-test and welch two sample t-test From…

Answered: data: Dental by Gender t = 3.8623, df =…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the critical value for a 98% confidence level and a sample size of n=15.
Obtain the summary statistics for LWT graph and AGE graph. Construct a 95% confidence interval estimate for moms mean age.
Listed below are speeds (mi/h) measured from traffic on a busy highway. This simple random sample was obtained at 3:30 P.M. on a weekday. Use the sample data to construct a 98% confidence interval estimate of the population standard deviation. 64 60 60 57 60 53 61 60 61 69 59 66 LOADING... Click the icon to view the table of Chi-Square critical values. Question content area bottom Part 1 The confidence interval estimate is 2.72.7 mi/h<σ<7.87.8 mi/h. (Round to one decimal place as needed.) Part 2 Does the confidence interval describe the standard deviation for all times during the week? Choose the correct answer below. A. Yes. The confidence interval describes the standard deviation for all times during the week. B. No. The confidence interval is an estimate of the standard deviation of the population of speeds at 3:30 on a weekday, not other times.
Related-Samples T-Test Pair 1 Before After - Mean -3.66667 Related-Samples T-Test Std. Deviation 4.41210 Mean Std. Deviation 3.20936 Pair 1 Before After -4.50000 Paired Samples Test Paired Differences Std. Error Mean 1.80123 Std. Error Mean 95% Confidence interval of the Paired Samples Test Paired Differences 1.31022 1. Look at the above Related-Samples t-Test SPSS output and use it to answer the following questions. a. Assume that the researcher is doing a 2-tailed test with a = .05. Should the researcher Reject Ho? T-test p-value: Reject Ho? Yes or No: b. Calculate the Cohen's d for effect size. c. Write out the APA summary for this test. c. Write out the APA summary for this test. Difference Lower -8.29689 Upper t 96355 -2.036 95% Confidence Interval of the Difference Lower -7.86802 df Upper t -1.13198 -3.435 5 df 5 Sig. (2-tailed) 097 Sig. (2-tailed) 019 2. Look at the above Related-Samples t-Test SPSS output and use it to answer the following questions. a. Assume that the…
Salma claimed that the gas price in Blue Park neighborhood (mean of $3.65) is higher than that in Green Spring (mean of $3.59). She obtained the t-value of 2.223 after calculating data from 6 gas stations in Blue Park and 5 gas stations in Green Spring. Use the chart below and determine if Salma's claim is supported! Table 10-3. Critical values of "t" significance level p= 0.05 significance level p= 0.01 TP 1 12.706 63.657 2 4.303 9.925 3 3.182 5.841 2.776 4.604 5 2.571 4.032 6 2.447 3.707 7 2.365 3.499 2.306 3.355 9 2.262 3.250 10 2.228 3.169 11 2.201 3.106 Copy the following into your text box, fill in the blanks, and answer the questions A. The degree of freedom is: B. The t-calculated value is: and the t-critical value is : C. Comparison: t-calc t-crit (answer with ()) D. Is the null hypothesis accepted or rejected? Explain how you determined that! Also, explain what it means to reject or accept the hypothesis! E. Explain if Salma's claim is supported based on your t-value…
Using 0.05 level of significance and assuming that the data is normally distributed: • Test the claim which tells that the mean weight is greater than 147 pounds. Additionally, construct a 95% confidence interval for the mean weight of the respondents.
I conduct an online study to determine whether rewards reduce procrastination. All participants are asked to complete a task sometime before a deadline (10 days from now). The computer randomly assigns participants to one of three groups, and emails them their instructions; one group receives a reward as soon as they do the task (contingent reward); a second group receives rewards as soon as they finish the task as long as it is before the deadline (non-contingent reward) and the third group does not receive rewards at all (no reward). Three participants in the no reward condition do not complete the task, and so are dropped from analyses. The dependent variable is the amount of time (in days) it takes participants to complete the task. The JAMOVI output is attached. What are possible threats to internal validity in this study (select all that apply)? ANOVA ANOVA - Time Reward Residuals 0.056 Assumption Checks Homogeneity of Variances Test (Levene's) F df1 Statistic 0.964 Sum of…
Pls answer
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