Data are given for the melting points for 50 metal alloy filaments. Here the data are repeated:320 326 325 318 322 320 329 317 316 331320 320 317 329 316 308 321319 322 335318 313 327 314 329 323 327 323 324 314308 305 328 330 322 310 324 314 312 318313 320 324 311 317 325 328 319 310 324Test the hypothesis that these are observations of a normally distributed random variable with signif-icant level 0.05. Note that you must estimate two parameters u and a

Test for Normality – Chi-square Test for Goodness of Fit

Answered: Data are given for the melting points…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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touch ".llE 55% D14:52 Question Measurements for the length and width of a rectangular plastic covers for CDs are Tounded to the nearest mm (so they are discrete). Let X denote the length and Y dente the width. The possible values of X are 129, 130, and 131 mm. The possible values of Y are 15 and 16 mm. The joint distribution is given by the following table X-length 129 130 131 Y=width 15 0.12 0.42 006 16 0.08 0.28 0.04 The probability that a CD cover has width of 16 mm knowing that it has a length of 131 mm is O 0.13 O 0.2 O 0.4 O 0.08
3.) A population has a mean of 300 and a variance of 80. If we get 160 samples from this population, what wili be the mean and standard deviation of the sampling distribution of sample mean? A.) Hg = 300 and og =0.53 B.) µg = 300 and og =0.71 C.) µg = 300 and og =6.32 D.) µg = 300 and og =80 %3D %3D
The following data represent petal lengths (in cm) for independent random samples of two species of iris. Petal length (in cm) of Iris virginica: x1; n1 = 36 5.2 5.6 6.1 6.1 5.1 5.5 5.3 5.5 6.9 5.0 4.9 6.0 4.8 6.1 5.6 5.1 5.6 4.8 5.4 5.1 5.1 5.9 5.2 5.7 5.4 4.5 6.4 5.3 5.5 6.7 5.7 4.9 4.8 5.8 5.2 5.2 Petal length (in cm) of Iris setosa: x2; n2 = 38 1.6 1.8 1.4 1.5 1.5 1.6 1.4 1.1 1.2 1.4 1.7 1.0 1.7 1.9 1.6 1.4 1.5 1.4 1.2 1.3 1.5 1.3 1.6 1.9 1.4 1.6 1.5 1.4 1.6 1.2 1.9 1.5 1.6 1.4 1.3 1.7 1.5 1.5 (a) Use a calculator with mean and standard deviation keys to calculate x1, s1, x2, and s2. (Round your answers to four decimal places.) x1=s1=x2=s2= (b) Let μ1 be the population mean for x1 and let μ2 be the population mean for x2. Find a 99% confidence interval for μ1 − μ2. (Round your answers to two decimal places.) lower limitupper limit
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b. The frequency distribution for the values of resistance in ohms of 48 resistors is as shown. Calculate the standard deviation from the mean of the resistors, correct to 3 significant figures. class frequency 20.5-20.9 3 21.0-21.4 10 21.5-21.9 11 22.0-22.4 13 22.5-22.9 9 23.0-23.4 2 Draw an ogive for this data and hence determine the quartile values.
Parts a-d
answer d)
For numbers 18 to 21: A study was conducted using 50 undergraduates at a large private university who volunteered to participate in the research as partial fulfillment of a Course requirement. One of the items studied was the mavimum daily amount of alcohol consumed in the last month. Base on the data in the following table are there differences between males and females in the maximum amount of alcohol consumed in any one day in the past month? Use 5 70 lev significance. Assume equal variances. Alcohol consumed Male female Mean 8.2 5.6 Standard deviation 5.9 5.7 Number of students 20 30 18. Which of the following is the appropriate alternative hypothesis? A. There are more female participants than males B. The amount of alcohol consumed by males is higher than the amount consumed by the females. C. The amount of alcohol consumed by males and females in the past month is not the same. D. The amount of alcohol consumed by males and females in the past month is the same. 19. The pooled…
Christmas is around the corner and people are rushing to purchase gifts. About 12 random customers reported how much they spent (in R) on gifts at a certain store in preparation for the 25 December celebration. The data are as follows: 191 189 181 102 125 160 143 159 100 103 82 89 where the third and fourth sample moments are Ma = 6982.407 and M. = 3294249. a. 32% of the customers spent at least Answer b. 22% of the customers spent at most Su c. The unbiased sample standard deviation is d. Calculate the standardised measure of kurtosis e. (option a) : The data is platykurkic.(option b) : The data is leptokurtic. (option c) : The data is mesokurtic.
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A stemplot for a set of data is given below. What is the shape of the distribution? Stem Leaf 267 36 4228 5 1469 6 4589 7 225669 8 00112347899 9011223344456668889 10 155666777 11 1377 12 a. symmetrical b. skewed to the left c skewed to the right d. bimodal 1.

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