The following data represent petal lengths (in cm) for independent random samples of two species of iris.Petal length (in cm) of Iris virginica: x,; n, = 365.05.66.56.15.15.55.35.56.95.04.96.04.86.15.65.15.65.9 | 5.26.4 5.34.85.45.15.15.75.44.55.56.75.74.94.8 5.85.2| 5.2Petal length (in cm) of Iris setosa: x,; n, = 381.41.61.41.51.51.61.41.11.21.41.71.01.71.91.61.41.5 1.41.21.31.51.31.61.91.41.61.51.41.61.21.91.51.6 1.41.31.71.51.7n USE SALT(a) Use a calculator with mean and standard deviation keys to calculate x, s,, x2, and sz. (Round your answers to four decimal places.)X1s, =S1x, =X2S2(b) Let u, be the population mean for x, and let u, be the population mean for x,. Find a 99% confidence interval for u, - Hg. (Round your answers to two decimal places.)lower limitupper limit

The data shows the petal lengths of Iris virginica, and petal length of Iris setosa.

Answered: (a) Use a calculator with mean and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

If n=29, x¯=48, and s=13, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population.( , )Give your answers to one decimal place.
If n = 20, the sample mean = 250, SD = 15, SEM = 3.354, what is the confidence interval (using 95% confidence level). What percent confidence do you have that the population mean is between what two values
Use the given data to construct a confidence interval for the population proportion p of the requested level. =x53 , =n68 , confidence level 80% Round the answers to at least three decimal places.
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
A statistics teacher taught a large introductory statistics class, with 500 students having enrolled over many years. The mean score over all those students on the first midterm was u = 88 with standard deviation o = 10. One year, the teacher taught a %3D much smaller class of only 25 students. The teacher wanted to know if teaching a smaller class was more effective and students performed better. We can consider the small class as an SRS of the students who took the large class over the years. The average midterm score was = 78. The hypothesis should be: a. Ho: H = 78 vs. Ha: H = 88. %3D O b. Ho: µ = 88 vs. Ha: µ 78 %3D Ο d. Ho: μ-88 νs. Ha: μ >88. %3D
There are several sections of Statistics; some in the morning and some in the afternoon. We randomly select n1 40 from the morning section and 44 from the afternoon section. The averages n2 of their scores are X1 76.3 for the morning section and X, = 71.9 for the afternoon section. The known standard deviations of their scores are 01 12.05 for the morning section and 02 13.06 for the afternoon section. Test the claim that the average for all students in the morning and afternoon section is the same. Use a a = 0.05 significance level. a. What is the negative critical region? Give your answer to two decimal places. z c. What is the test statistic? Give your answer to two decimal places. z = d. Do we reject or fail to reject the null hypothesis? OReject Ho OFail to reject Họ
Write down the confidence interval formula for image 1 . Is the correct answer image 2?
For normal population, the sample mean M = 35 has the same absolute value of the Z – score as a sample mean M = 43. The two samples have the same sample size in. What is the population mean?
A mean function E(Y IX = x) tells us: the probability of observing the value Y. O whether or not to reject the null hypothesis. how much data we need to collect. how the expected value of Y changes as X varies.
A set of 11 data pairs (x.y) were collected and were found to have a linear relationship given by: y = 3.04 x + 0.99 The Standard Error of the Fit for this equation is 0.755 and the confidence interval, CI, is written as: y = ax + b+ (e) Provide the value of the margin of error, e, at a confidence level of 95%. (Use 3 decimal places to express your answer).
Solve Question 2 Please show work
ANSWER PART B ONLY

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