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Figure 1 shows sample means from
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μ=
SE=
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- Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10 significance level to test for a difference between the measurements from the two arms. Identify the test statistic and p-value. Right arm Left arm 144 167 OA.T-3.07, p-value = 0.037 OB. T = -2.32, p-value = 0.081 OC. T = -1.93, p-value = 0.127 OD. T = -4.01, p-value = 0.016 133 161 132 179 138 145 136 144One group of accounting students took a distance learning class, while another group took the same course in a traditional classroom. At α = .10, is there a significant difference in the mean scores listed below? Exam Scores for Accounting Students Statistic Distance Classroom Mean scores x⎯⎯1x¯1 = 9.0 x⎯⎯2x¯2 = 10.2 Sample std. dev. s1 = 2.1 s2 = 2.4 Number of students n1 = 19 n2 = 19 Assume μ1 is the mean score of distance learning and μ2 is the mean score of classroom learning. The appropriate hypotheses is H0: μ1 – μ2 = 0 vs. H1: μ1 – μ2 ≠ 0 (b) Specify the decision rule. (Round your answers to 3 decimal places. A negative value should be indicated by a minus sign.) Reject the null hypothesis if tcalc < _______. Or tcalc > ______________. (c) Find the test statistic tcalc. (Round your answer to 4 decimal places. A negative value should be indicated by a minus sign.) tcalc ______________A simple random sample of size n = 18 is drawn from a population that is normally distributed. The sample mean is found to be x = 23.9 and the sample standard deviation is found to be s = 6.6. Determine if the population mean is different from 26 at the a = 0.01 level of significance. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Click here to view the table of critical t-values. ..... (a) Determine the null and alternative hypotheses. Ho: H 26 = H,: H 26 (Type integers or decimals. Do not round.) (b) Identify the test statistic. (Round to two decimal places as needed.)
- Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributedpopulations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Diet Regular μ μ1 μ2 n 33 33 x 0.78488 lb 0.80356 lb s 0.00444 lb 0.00744 lb a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. i) What are the null alternative hypothesis? ii) What's the test statics? iii) What's the P-value? iv) State the conclusion vi) construct a confidence interval suitable suitable for testing the claim that the two samples are from populations with the same mean vii) Does the confidence interval…Gentle Ben is a Morgan horse at a Colorado dude ranch. Over the past 8 weeks, a veterinarian took the following glucose readings from this horse (in mg/100 ml). 91 88 82 103 97 108 84 91 The sample mean is x ≈ 93.0. Let x be a random variable representing glucose readings taken from Gentle Ben. We may assume that x has a normal distribution, and we know from past experience that ? = 12.5. The mean glucose level for horses should be ? = 85 mg/100 ml.† Do these data indicate that Gentle Ben has an overall average glucose level higher than 85? Use ? = 0.05. (a) What is the level of significance? State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? H0: ? = 85; H1: ? > 85; right-tailed H0: ? > 85; H1: ? = 85; right-tailed H0: ? = 85; H1: ? ≠ 85; two-tailed H0: ? = 85; H1: ? < 85; left-tailed (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution.…Heights for teenage boys and girls were calculated. The mean height for the sample of 50 boys was 167 cm and the variance was 57. For the sample of 56 girls, the mean was 153 cm and the variance was 67. There is no reason to assume the variances would be equal. Estimate how much taller teenage boys are using a 99% confidence level. Express this in the (point estimate) ± (margin of error) format. Round answers to 2 decimal places. H
- Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm 146 137 140 132 132 Left-arm 183 172 179 156 149 In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test? Identify the test statistic. Identify the P-value.Question 2 Full explain this question and text typing work only plzTest the claim below about the mean of the differences for a population of paired data at the level of significance a. Assume the samples are random and dependent, and the populations are normally distributed. Claim: 0 В. Но На > 0 Ha: Ha s0 O C. Ho: Ha = 0 Ha: Hd #0 D. Ho: Ha <0 Ha: Hd 20 O E. Ho: Hd + 0 Ha: Hd F. Ho: Hd 20 Ha: Hd = 0 <0 The test statistic is t= (Round to two decimal places as needed.)
- Gentle Ben is a Morgan horse at a Colorado dude ranch. Over the past 8 weeks, a veterinarian took the following glucose readings from this horse (in mg/100 ml). 94 87 83 104 98 108 84 89 The sample mean is x = 93.4. Let x be a random variable representing glucose readings taken from Gentle Ben. We may assume that x has a normal distribution, and we know from past experience that o = 12.5. The mean glucose level for horses should be u = 85 mg/100 ml.t Do these data indicate that Gentle Ben has an overall average glucose level higher than 85? Use a = 0.05. (a) What is the level of significance? State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? O Ho: H = 85; H,: u + 85; two-tailed O Ho: H = 85; H: µ > 85; right-tailed O Ho: H > 85; H,: µ = 85; right-tailed O Ho: H = 85; H,: µ < 85; left-tailed (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. O The Student's t, since we assume…Heights for teenage boys and girls were calculated. The mean height for the sample of 51 boys was 183 cm and the variance was 66. For the sample of 71 girls, the mean was 173 cm and the variance was 61. There is no reason to assume the variances would be equal. Estimate how much taller teenage boys are using a 87% confidence level. Express this in the (point estimate) ± (margin of error) format. Round answers to 2 decimal places. HA population of values has a normal distribution with u = 36 and o = 31.3. You intend to draw a random sample of size n = 12. Please answer the following questions, and show your answers to 1 decimal place. Find the value separating the bottom 11% values from the top 89% values. Find the sample mean separating the bottom 11% sample means from the top 89% sample means.
