Data and Calculations: Pure Water Methanol in Water Volume of Water (ml) 10.00 10.00 Mass of Methanol (g) Freezing Point ('C) Freezing point depression AT- Calculate the molality m (K, = 1.86 °C/m for water) 1.00 Tsolvent = 1 AT, = Tsolvent – Tsotution = AT; = Kr.m → m = AT;/Kf = Tsotution= -4.5 m = moles methanol/ Kg solvent → moles methanol m x Kg solvent = Calculate number of moles Calculate the molar mass of methanol moles methanol = mass methanol / molar mass methanol → molar mass methanol = mass methanol / moles methanol → molar mass methanol = 1.00 g/ moles methanol % error (actual molar mass of methanol = %error =[ ]actual – experimental| / actual ] x 100% 32.04 g/mol) Question: 1. What is the freezing point of a solution prepared by dissolving 20 g of ethanol (Molar mass = 46 g/mol) in 120 mL of water? The freezing point depression constant Kf for water is 1.86 °C/m. Assume density of water is 1 g/ml.

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Data and Calculations:
Pure Water
Methanol in Water
Volume of Water (ml)
10.00
10.00
Mass of Methanol (g)
Freezing Point (°C)
Freezing point depression AT
Calculate the molality m
(K, = 1.86 °C/m for water)
1.00
Tsotution =
Tsolvent = 1
AT, = Tsotvent –Tsolution =
AT; = Kf.m → m = AT;/Kf =
-4.5
m = moles methanol/ Kg solvent
→ moles methanol = m x Kg solvent =
moles methanol = mass methanol / molar mass methanol
molar mass methanol = mass methanol / moles methanol
molar mass methanol = 1.00 g / moles methanol
Calculate number of moles
Calculate the molar mass of methanol
% error (actual molar mass of methanol = % error =[ |actual – experimental| / actual ] x 100%
32.04 g/mol)
Question:
1. What is the freezing point of a solution prepared by dissolving 20 g of ethanol (Molar mass =
46 g/mol) in 120 mL of water? The freezing point depression constant K, for water is 1.86 °C/m.
Assume density of water is 1 g/ml.
Transcribed Image Text:Data and Calculations: Pure Water Methanol in Water Volume of Water (ml) 10.00 10.00 Mass of Methanol (g) Freezing Point (°C) Freezing point depression AT Calculate the molality m (K, = 1.86 °C/m for water) 1.00 Tsotution = Tsolvent = 1 AT, = Tsotvent –Tsolution = AT; = Kf.m → m = AT;/Kf = -4.5 m = moles methanol/ Kg solvent → moles methanol = m x Kg solvent = moles methanol = mass methanol / molar mass methanol molar mass methanol = mass methanol / moles methanol molar mass methanol = 1.00 g / moles methanol Calculate number of moles Calculate the molar mass of methanol % error (actual molar mass of methanol = % error =[ |actual – experimental| / actual ] x 100% 32.04 g/mol) Question: 1. What is the freezing point of a solution prepared by dissolving 20 g of ethanol (Molar mass = 46 g/mol) in 120 mL of water? The freezing point depression constant K, for water is 1.86 °C/m. Assume density of water is 1 g/ml.
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