D3.4. Calculate the total electric flux leaving the cubical surface formed by the six planes x, y, z = +5 if the charge distribution is: (a) two point charges, 0.1 µC at (1, -2, 3) and 1/7 uC at (-1, 2,-2); (b) a uniform line charge of a uC/m at x = -2, y = 3; (c) a uniform surface charge of 0.1 uC/m on the plane y 3x. %3D %3D

D3.4. Calculate the total electric flux leaving the cubical surface formed by the six planes x, y, z = +5 if the charge distribution is: (a) two point charges, 0.1 µC at (1, -2, 3) and 1/7 uC at (-1, 2,-2); (b) a uniform line charge of a uC/m at x = -2, y = 3; (c) a uniform surface charge of 0.1 uC/m on the plane y 3x. %3D %3D

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

What is the net electric flux passing through a cylindrical surface shown below, whose axis is the dashed line? The cylindrical surface is of diameter 4.0 cm, and a length of 15.0 cm, with its axis parallel to, but offset radially by 1.0 cm, from an infinitely long line of charge having a uniform linear charge density A = 3.0 μC/m? The line of charge is the solid line. 1.0 cm 10 O 4.4 x 10³ Nm²/C O 8.7 x 10³ Nm²/C O 1.8 x 105 Nm²/C O 5.1 x 104 Nm²/C O 7.6 x 104 Nm²/C 2 h
A charge distribution creates the following electric field throughout all space: E(r, 0, q) = (3/r) (r hat) + 2 sin cos sin 0(theta hat) + sin cos p (phi hat). Given this electric field, calculate the charge density at location (r, 0, p) = (ab.c).
Just need #7, but need values from #6.
Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: ĐE - dA = EA = Since, its the line charge we use the area of a cylinder surrounding the line charge E*2 TT L= But all the charged get enclosed by the cylinder area, so denc = Q Deriving, we get: E = (1/2 TEO )*( IrL)
1. In the figure, the hemispherical shell has a charge density and radius a. (a) Find the total charge contained in the annulus (marked in blue) whose own center is a distance x' away from the hemispherical center C in terms of the givens. (b) Find the electric field contribution of this annulus to the total electric field at the field point P a distance x, from the aforementioned center. P of x=d х=хо с X-axis
Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: PE - dÀ = EA = | E0 Since, its the line charge we use the area of a cylinder surrounding the line charge E*2T L= But all the charged get enclosed by the cylinder area, so denc = Q Deriving, we get: E = (1/2 TE0 )*( /rL)
(a) Three point charges are located on the circumference of a circle of radius r, at the angles shown in the figure. 150° O 30° 270⁰ What is the electric field at the center of the circle due to these point charges? (Express your answer in vector form. Use the following as necessary: Ker q, and r.) 3k 3424 (-1) (b) What If? What is the minimum electric field magnitude that could be obtained at the center of the circle by moving one or more of the charges along the circle, with a minimum separation of 3.90° between each of the charges? Express your result as the ratio of this new electric field magnitude to the magnitude of the electric field found in part (a). Eminimum 0.0015 X Epart (a) Place the two charges +q at 0 = 270° ± y, where y is the smallest angle at which the charges do not overlap with the charge -2q, then write an expression for the electric field at the center.
Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: DE - dÀ = EA = Since, its the line charge we use the area of a cylinder surrounding the line charge E*2T L= But all the charged get enclosed by the cylinder area, so denc = Q Deriving, we get: E= (1/2 TE0 )*( IrL)
A spherical charge distribution of radius R is given by ρ = ρ0(1 – r/R), where r is the radial distance and ρ is the volume charge density. The electric field E is maximum at r equals: Zero 2.0R R/3 2R/3 0.745R Clear my choice
4
Please don't provide handwritten solution .....
What is the scalar electric field strength 12 mm away perpendicularly from the center of a ring of charge with 15mm radius and has a total charge of +750 uC. note: Answer in GN/C and 3 decimal places