Calculate the electric field in N/C at point P, a distance (1.259x10^1) cm above an infinite plane of charge with charge density +(7.06x10^0) µC/m². You do not need to enter a unit vector in your answer, but must put a negative sign in, if the electric field is pointing along the negative z-axis.
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- Consider a thin, spherical shell of radius 14.5 cm with a total charge of 29.9 µC distributed uniformly on its surface. (a) Find the electric field 10.0 cm from the center of the charge distribution. (b) Find the electric field 24.5 cm from the center of the charge distribution.Consider a cylindrically symmetric distribution of charge. It consists of a tube of charge of radius 0.6 m with a linear charge density of 284.8 x 10-12 C/m that is surrounded by a second tube of charge of radius 4.1 m with linear charge density -188.5 x 10-12 C/m. Calculate the magnitude of the electric field, in N/C, 1.7 m away from the axis of the distribution. Use ?0ε0 = 8.85 x 10-12 F/m. (Please answer to the fourth decimal place - i.e 14.3225)A uniformly charged disk of radius R=25 cm carries a total charge of Q=2 μC. R P 1 Find the magnitude of the electric field E created by the disk at the point P located at distance 40 cm from the center of the disk. E = [N/C] 2. What is the direction of the electric field E created by the disk at point P. Direction: 3. Write the expression of the electric filed E created by the disk at point P. Ē =< [N/C] 4. Find the magnitude of the electric field E created by the disk at the point P located at distance 8 m from the
- An electric field 7 N/C is passing through a region of area 2.1 m² in the xy-plane. If the electric field makes an angle of 56° with respect to the area vector perpendicular to the region, calculate the electric flux magnitude (in N-m²/C) through the region.A closed surface with dimensions a = b = 0.461 m and c = 0.7837 m is located as in the figure. The electric field throughout the region is nonuniform and defined by E (a + Bx²) î where x is in meters, a = 3 N/C, and 3 = 5 N/(C. m²). Y E C. b X What is the magnitude of the net charge enclosed by the surface? Answer in units of C. Answer in units ofA hollow sphere of radius .05m contains a negative charge sitting right at its center. (The sphere itself is not charged.) The electric field everywhere on the surface of the sphere has the magnitude 3.0*10^-4 N/C. Draw the sphere and show the electric field vectors on your drawing. What is the total electric flux through the surface of the sphere?
- For a given surface, the electric flux, PE, is proportional to the number of field lines through the surface. For a uniform electric field, the maximum electric flux is equal to the product of electric field at the surface and the surface area (i.e., EA). The electric flux is defined to be positive when the electric field E has a component in the same direction as the area vector A and is negative when the electric field has a component in the direction opposite to the area vector. C. Sketch vectors A and Ē such that the electric flux is: Positive Negative ZeroCalculate the electric field in N/C at point P, a distance (4.35x10^1) cm along the central axis of a disk of charge with radius (9.157x10^0) cm, and charge density +(8.0860x10^0) µC/m2. You do not need to enter a unit vector in your answer, but must put a negative sign in, if the electric field is pointing along the negative z-axis. RA nonuniform electric field is directed along the x-axis at all points in space, as shown in the figure. The diameter of the cylindrical surface id of 0.20 m. If the electric fields E1 and E2, at the ends of the cylindrical surface, have magnitudes of 2009.5 N/C and 1193.7 N/C respectively, find the net charge (in pC) in this cylindrical surface? 0.20 m E 0.80 m a. 890.59 Ob.-2268.18 O C. -226.82 O d. -890.59 O e. 226.82